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3 years ago

7. A beam of light converges at a point P. Now a lens is placed in the path of the convergent

Physics

1 answer:

Rudiy273 years ago

5 0

Answer:

Lens at a distance = 7.5 cm

Lens at a distance = 6.86 cm (Approx)

Explanation:

Given:

Object distance u = 12 cm

a) Focal length = 20 cm

b) Focal length = 16 cm

Computation:

a. 1/v = 1/u + 1/f

1/v = 1/20 + 1/12

v = 7.5 cm

Lens at a distance = 7.5 cm

b. 1/v = 1/u + 1/f

1/v = 1/16 + 1/12

v = 6.86 cm (Approx)

Lens at a distance = 6.86 cm (Approx)

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In pushes a 500 N crate with an applied force of 1450 N to the left. He encounters a fridtional force of 200 N and his evil co-w

Butoxors [25]

Answer:

C. 750 N. left

Explanation:

let the force to the right be positive, and the left be negative

Step one:

given

mass of crate m= 500N

1450N force left

Frictional force of 200 N -----this opposes the motion

500 N opposing force to the right

The net force is equal to the summation of all the forces in Newton

Net force= -1450+200+500

Net force=-750N

The direction is right

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2 years ago

A toy car has a momentum of 3 kilogram meters per second south. The car has a 1-kilogram mass. Which is the velocity of the car?

antiseptic1488 [7]

Using p = mv 3 = 1× v v = 3m/s

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2 years ago

What is the value for the kinetic energy for a n = 5 Bohr orbit electron in zeptoJoules?

Ne4ueva [31]

Answer:

The kinetic energy is 86.6 zepto joules.

Explanation:

Given that,

Number of orbit n =5

We know that,

Bohr's radius for hydrogen atom is

$r = 0.53\times10^{-10}\times n^2\ m$

Now, put the value of n in the formula of radius

$r=0.53\times10^{-10}\times5^2$

$r =1.33\times10^{-9}\ m$

We need to calculate the kinetic energy

Using formula of kinetic energy

$E_{k}=\dfrac{1}{4\pi\epsilon_{0}}\times\dfrac{e^2}{2\times r_{s}}$

Put the value into the formula

$E_{k}=\dfrac{9\times10^{9}\times(1.6\times10^{-19})^2}{2\times1.33\times10^{-9}}$

$E_{k}=8.66\times10^{-20}\ J$

We know that,

$1\ zepto\ joule=1\times10^{-21}\ J$

The kinetic energy is

$E_{k}=\dfrac{8.66\times10^{-20}}{1\times10^{-21}}$

$E_{k}=86.6\ zepto\ Joules$

Hence, The kinetic energy is 86.6 zepto joules.

8 0

3 years ago

Help me please i dont understand

Mamont248 [21]

Answer:

0.58

Explanation:

Sinẞ = opposite ÷ hypotenuse

Sinẞ = 5 ÷ 8.6

Sinẞ = 0.5814

Sinẞ ≈ 0.58

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2 years ago

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You have discovered a planet that is one-quarter the radius of Earth (Rp = 1/4R⊕) and one-half as massive (Mp = 1/2M⊕). How does

ExtremeBDS [4]

It's 8 times as much as before.

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2 years ago