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3 years ago

Which statement are true about moving the compass around the wire? Check all that apply

Physics

2 answers:

hoa [83]3 years ago

7 0

With no current, the compass needle will not move.

If the light bulb is on, the compass needle will move.

Changing the battery terminals will change the current flow and the compass will point differently

yanalaym [24]3 years ago

4 0

The following apply among the choices;

1. With no current, the compass needle will not move

2. If the light bulb is on, the compass needle will move

3. Changing the battery terminals will change the current flow and the compass will point differently

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a truck was traveling at 16.6 miles per second and accelerates at a rate of 2.0 meters per second squared how much time is requi

Ivan

A truck was traveling at 16.6 miles per second and accelerates at a rate of 2.0 meters per second squared then time is required for the truck to reach a speed of 25 miles per second is 6759 s.

Explanation:

Velocity is defined as the rate of change in displacement while acceleration is defined as the rate of change of velocity. Acceleration may be positive or negative. Acceleration is positive when the velocity of the object is increases and it is negative when velocity of the object is decreases. Negative acceleration is also called deceleration.

Mathematically

a = $\frac{(v_{f} - v_{i})}{t}$

Where a is the acceleration of the object, $v_{f}$ is the final velocity of the object and $v_{i}$ is the initial velocity of the object. t is equal to time taken.

Given data:

$v_{f}$ = 25 miles/s

$v_{i}$ = 16.6 miles/s

a = 2.0 m/s²

t = ?

As velocities and acceleration given in different units, So we need to convert to obtain same units. Here we convert unit of acceleration from m/s² to miles/s².

1 m/s² = 0.000621371192 miles/s²

2 m/s² = 0.00124274238 miles/s²

So,

a = 0.00124274238 miles/s²

Apply formula

a = $\frac{v_{f} - v_{i}}{t}$

t = $\frac{(v_{f} - v_{i})}{a}$

t = $\frac{(25 - 16.6)}{0.00124274238}$

t = 6759 s

Learn more about velocity and acceleration from

brainly.com/question/1192983

#learnwithBrainly

3 0

3 years ago

Two wave pulses move toward each other along a rope.

mojhsa [17]

Answer:

The answer is B. It is the one that has the triangle pointing up on the topside of the rope and seems to be a bit bigger than the other triangles.

Explanation:

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3 years ago

Read 2 more answers

Một trụrỗng có khối lượng 50 kg, đường kính 1m, đang quay vớivận tốc800 vòng một phút. Tác dụng vào trụmột lực hãm tiếp tuyến vớ

satela [25.4K]

Answer:

i now peklat mo sa pewet

Explanation:

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6 0

3 years ago

Which produces more energy:

Leya [2.2K]

Answer:

a) uranium

b) deuterium

Explanation:

For the first question, you can actually know this by simple logic. The nucleus of Ucranium, has more energy than a pair of deuterium. Ucranium has a mass number and atomic mass higher than deuterium, therefore, when you do a fission with ucranium in it's nucleous, this would be in energy higher than the deuterium.

However, in terms of mass only, the fissioning of 1 gram of Deuterium will produce more energy than 1 gram of uranium, basically because deuterium is lighter and has a lower molecular weight than ucranium. This means that because of this lower molecular weight, in 1 gram of deuterium will contain more number of atoms than in 1 g of uranium. The interaction with these atoms, will produce more energy than the energy produced by uranium.

3 0

3 years ago

In a car lift used in a service station, compressed air exerts a force on a small piston that has a circular cross section and a

timofeeve [1]

Answer:

a) F₁ = 1.48 x 10³ N

b) P = 1.88*10⁵ Pa

c) The work is equal in both pistons

Explanation:

Pascal´s Principle can be applied in the hydraulic press:

If we apply a small force (F₁) on a small area piston (A₁), then, a pressure (P) is generated that is transmitted equally to all the particles of the liquid until it reaches a larger area piston and therefore a force (F₂) can be exerted that is proportional to the area(A₂) of the piston.

Pressure is defined as the force per unit area:

$P=\frac{F}{A}$ Formula (1)

P₁=P₂

$\frac{F_{1} }{A_{1} } =\frac{F_{2} }{A_{2} }$ Formula (2)

Data

r₁= 5 cm = 0.05 m

r₂= 15 cm = 0.15 m

F₂= 13300N

Area of the pistons (A₁,A₂)

A=π*r² : Area of the circle

A₁ = π*(0.05)²=7.85*10⁻³ m²

A₂= π*(0.15)²= 70.69*10⁻³ m²

a) Force that compressed air must exert to lift a car weighing 13300 N

We replace data in the formula (2)

$\frac{F_{1} }{A_{1} } =\frac{F_{2} }{A_{2} }$

$F_{1} = \frac{13300*7.85*10^{-3} }{70.69*10^{-3} }$

F₁ = 1.48 x 10³ N

b) Air pressure produced by F₁

We replace data in the formula (1)

$P=\frac{F}{A}$

F₁ = 1.48 x 10³ N , A₁ = 7.85*10⁻³ m²

$P=\frac{1.48*10^{3} }{7.85*10^{-3} }$

P= 1.88*10⁵ Pa

c)The volume of liquid displaced by the small piston is distributed in a thin layer on the large piston, so that the product of the force by the displacement (the work) is equal in both pistons.

3 0

3 years ago