Answer:
The capillary rise of the glycerin is most nearly ![y = 0.0204 \ m](https://tex.z-dn.net/?f=y%20%20%3D%20%200.0204%20%5C%20m)
Explanation:
From the question we are told that
The diameter of the glass tube is ![d = 1 \ mm = 0.001 \ m](https://tex.z-dn.net/?f=d%20%3D%20%201%20%5C%20mm%20%3D%20%200.001%20%5C%20m)
The density of glycerin is ![\rho = 1260 \ kg /m^3](https://tex.z-dn.net/?f=%5Crho%20%3D%20%201260%20%5C%20kg%20%2Fm%5E3)
The surface tension of the glycerin is ![\sigma = 6.3 *10^{-2} \ N /m](https://tex.z-dn.net/?f=%5Csigma%20%20%20%3D%20%206.3%20%2A10%5E%7B-2%7D%20%5C%20N%20%2Fm)
The capillary rise of the glycerin is mathematically represented as
![y = \frac{4 * \sigma * cos (\theta )}{ \rho * g * d}](https://tex.z-dn.net/?f=y%20%20%3D%20%20%5Cfrac%7B4%20%2A%20%5Csigma%20%20%2A%20%20cos%20%28%5Ctheta%20%29%7D%7B%20%5Crho%20%2A%20g%20%2A%20%20d%7D)
substituting value
![y = \frac{4 * 6.3 *10^{-2} * cos (0 )}{ 1260 * 9.8 * 0.001}](https://tex.z-dn.net/?f=y%20%20%3D%20%20%5Cfrac%7B4%20%2A%206.3%20%2A10%5E%7B-2%7D%20%20%2A%20%20cos%20%280%20%29%7D%7B%201260%20%2A%209.8%20%2A%20%200.001%7D)
![y = 0.0204 \ m](https://tex.z-dn.net/?f=y%20%20%3D%20%200.0204%20%5C%20m)
Therefore the height of the glass tube the glycerin was able to cover is
If these were the missing choices:
a)
Consumers fill out questionnaires concerning
their need for new products.
b)
Consumers vote for politicians who decide which
kind of research to support
c)
Consumers decide what to buy and what not to buy
d)
Consumers influence the decisions of private
foundations by deciding where to donate money.
My answer would be: c) <span>Consumers decide what to buy and what not to buy</span>
Every growth is based on the demand of the people. If a good or service is needed then its demand will increase. If a good or service is not needed then its demand will decrease until such time that said good or service will be eliminated.
Noble gases are not highly reactive
Answer:
There are three ways an object can accelerate: a change in velocity, a change in direction, or a change in both velocity and direction.
Explanation: