Answer:
The induced emf 1.43 s after the circuit is closed is 4.19 V
Explanation:
The current equation in LR circuit is :
.....(1)
Here I is current, V is source voltage, R is resistance, L is inductance and t is time.
The induced emf is determine by the equation :

Differentiating equation (1) with respect to time and put in above equation.


Substitute 6.05 volts for V, 0.655 Ω for R, 2.55 H for L and 1.43 s for t in the above equation.


According to Gauss' law, the electric field outside a spherical surface uniformly charged is equal to the electric field if the whole charge were concentrated at the center of the sphere.
Therefore, when you are outside two spheres, the electric field will be the overlapping of the two electric fields:
E(r > r₂ > r₁) = k · q₁/r² + k · q₂/r² = k · (q₁ + q₂) / r²
where:
k = 9×10⁹ N·m²/C²
We have to transform our data into the correct units of measurement:
q₁ = 8.0 pC = 8.0×10⁻¹² C
q₂ = 3.0 pC = 3.0×10<span>⁻¹² C
</span><span>r = 5.0 cm = 0.05 m
Now, we can apply the formula:
</span><span>E(r) = k · (q₁ + q₂) / r²
= </span>9×10⁹ · (8.0×10⁻¹² + 3.0×10⁻¹²) / (0.05)²
= 39.6 N/C
Hence, <span>the magnitude of the electric field 5.0 cm from the center of the two surfaces is E = 39.6 N/C</span>
Answer:
0.036J
Explanation:
Given parameters:
Spring constant , K = 92N/m
Compression = 2.8cm = 0.028m
Unknown:
Potential energy = ?
Solution:
To solve this problem;
P.E =
K e²
K is the spring constant
e is the compression
so;
P.E =
x 92 x 0.028² = 0.036J
Answer:
Explanation:
Given
radius of path 
Velocity of Particle 
where t=time in seconds
angular velocity of particle is given by


And angular acceleration is given by


tangential acceleration is 

Centripetal acceleration 

net acceleration is sum of tangential and centripetal force at any time t is given by



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