How to balance lead and silver acetate yields lead (||) acetate and silver
1 answer:
The given elements put into an equation using their symbols are as follows:
Pb +
= 
+ Ag
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + = + Ag
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
= + Ag
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + = + 2Ag
That is your final equation
The coefficients are 2 + 2 = 1 + 2
Pb +
Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb +
Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb +
Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb +
That is your final equation
The coefficients are 2 + 2 = 1 + 2
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According to Graham's Law ," the rates of effusion or diffusion of two gases are inversely proportional to the square root of their molecular masses at given pressure and temperature".
r₁ / r₂ =
---- (1)
r₁ = Rate of effusion of He
r₂ = Rate of Effusion of O₃
M₁ = Molecular Mass of He = 4 g/mol
M₂ = Molecular Mass of O₃ = 48 g/mol
Putting values in eq. 1,
r₁ / r₂ =
r₁ / r₂ =
r₁ / r₂ = 3.46
Result:
Therefore, Helium will effuse 3.46 times more faster than Ozone.
r₁ / r₂ =
r₁ = Rate of effusion of He
r₂ = Rate of Effusion of O₃
M₁ = Molecular Mass of He = 4 g/mol
M₂ = Molecular Mass of O₃ = 48 g/mol
Putting values in eq. 1,
r₁ / r₂ =
r₁ / r₂ =
r₁ / r₂ = 3.46
Result:
Therefore, Helium will effuse 3.46 times more faster than Ozone.