Answer:
C. Technician B
Explanation:
Excessive Galvanic activity:
To check for excessive galvanic activity, voltmeter is used to check the coolant. If the voltmeter is giving a reading greater than 0.5 V, there is excessive galvanic activity. Excessive galvanic activity is solved by flushing the coolant fluid from engine and refiling it.
Electrolysis problem:
When the system is not properly ground, the cooling system accepts stray current and the coolant becomes an electrolyte which might eat up the radiator. To test for excessive electrolysis, start the engine and turn on all electrical accessories, if the reading is more than 0.5 V, there is electrolysis problem. Ground wires and connections should be checked at this point to stop stray current.
In our case, the first reading is 0.2 V(engine turned off) which is normal and there is no excessive galvanic activity. This means that Technician A is not correct. The second reading is 0.8 V when the engine and all electrical accessories are turned on. This reading is greater than 0.5 V which means there is an electrolysis problem. This means that Technician B is correct and ground wires and connections should be inspected and repaired.
Answer:
a. 1.75 Nm²/C
b. Yes.
Explanation:
a. Electric Flux is given as:
Φ = E*A*cosθ
Where E = electric flux
A = Surface area
Φ = 14 * 0.25 * cos60
Φ = 1.75 Nm²/C
b. Yes, the shape of the sheet will affect the Flux through it. This is because flux is dependent on area of the surface and the area is dependent on the shape of the surface.
Answer:
Reflection involves a change in direction of waves when they bounce off a barrier. Refraction of waves involves a change in the direction of waves as they pass from one medium to another.
Answer:
time
Explanation:
weather is the atmospheric condition of a place over a short period of time, while climate is the weather condition prevailing in an area over a long period of time. From the two definitions above we can see that weather is the condition over a short period of time while climate is over longer periods, therefore the primary difference between them is time.
The power equals energy divided by the time
P=E/t
P=1200/60
P=20W
Hope you get it!
