Answer:
The ratio of the young's modulus of steel and copper is 
(c) is correct option.
Explanation:
Given that,
Length of steel wire = 4.7 m
Cross section
Length of copper wire = 3.5 m
Cross section
We need to calculate the ratio of young's modulus of steel and copper
Using formula of young's modulus for steel wire
....(I)
The young's modulus for copper wire
....(II)
From equation (I) and (II)
The ratio of the young's modulus of steel and copper
Hence, The ratio of the young's modulus of steel and copper is
Answer:
Explanation:
a) series resistors carry the same current
A = V/Re = 6/(16 + 6) = 0.2727272... ≈ 27 mA
b) V = V₀(R/Re) = 6(16/(16 + 6)) = 4.363636 ≈ 4.4 V
c) V = V₀(R/Re) = 6(6/(16 + 6)) = 1.636363 ≈ 1.6 V
or V = 6 - 4.4 = 1.6 V
We have: v = d/t
From the expression, we conclude speed is indirectly proportional to speed.
So, the car which will take longer time must have the smallest speed. Among all the options Car C has the smallest speed. So, it would be your answer.
In short, Your Answer would be Option C) Car C will take longer time than any other.
Hope this helps!
She could tell by how many components she put in. The compounds, are like the ingredients. The Mixture is all the ingredients stirred together.
Answer:
Neither technician
Explanation:
Neither technician is correct.
two bulbs are connected in series one bulb burn out
If one bulb in the series burns out then the circuit will break.
In a series circuit same current passes each resistor.
so, both the technician is incorrect bulb B will not work and current will not increase in the other bulb.
