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kolbaska11 [484]
3 years ago
8

I need help!!! What is the answer!!

Physics
1 answer:
sergeinik [125]3 years ago
7 0

Answer:

A I think hope it helps!!

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A spaceship, at rest in some inertial frame in space, suddenly needs to accelerate. The ship forcibly expels 103 kg of fuel from
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Answer:

V_s = 1.8*10^5m/s

Explanation:

There is no external force applied, therefore there is a moment's preservation throughout the trajectory.

<em>Initial momentum  = Final momentum. </em>

The total mass is equal to

m_T= m_1 +m_2

Where,

m_1 = mass of ship

m_2 = mass of fuell expeled.

As the moment is conserved we have,

0=V_fm_2+V_sm_1

Where,

V_f = Velocity of fuel

V_s =Velocity of Space Ship

Solving and re-arrange to V_swe have,

V_s = \frac{V_f m_2 }{m_1}

V_s = \frac{3/5c}{10^6}

V_s = 3.5*10^{-3}c

Where c is the speed of light.

Therefore the ship be moving with speed

V_s = \frac{3}{5}*10^{-3}*3*10^8m/s

V_s = 1.8*10^5m/s

5 0
3 years ago
1) A fan is to accelerate quiescent air to a velocity of 8 m/s at a rate of 9 m3/s. Determine the minimum power that must be sup
azamat

Answer:

\dot{W} = 339.84 W

Explanation:

given data:

flow Q = 9 m^{3}/s

velocity = 8 m/s

density of air = 1.18 kg/m^{3}

minimum power required to supplied to the fan is equal to the POWER POTENTIAL of the kinetic energy and it is given as

\dot{W} =\dot{m}\frac{V^{2}}{2}

here \dot{m}is mass flow rate and given as

\dot{m} = \rho*Q

\dot{W} =\rho*Q\frac{V^{2}}{2}

Putting all value to get minimum power

\dot{W} =1.18*9*\frac{8^{2}}{2}

\dot{W} = 339.84 W

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Convection moves in a cicular motion 

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A spring is felxiable
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