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Svetach [21]
3 years ago
12

Joy uses 20n of force to shovel the snow 10 meters. how much work does she do? 200 j 2 j 30 j 100 j

Physics
1 answer:
levacccp [35]3 years ago
8 0
20 newtons divided by 10 meters 
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For an atom to be neutral the amount of ? and? must be equal
maks197457 [2]

Answer: Well first of all, for an Atom to be neutral, it shall have an equal number of the protons and the neutrons. So given that, the protons are able to be positively charged and since the electrons are negatively charged (Protons and Electrons are completely different from each other) then that means the Algebric are aggregated of charges because it equal to zero. So overall, the 'neutral atom' has to be neutral, and how? Protons must equal the number of electrons or else it wouldn't be considered neutral.

Hopefully this helps you very much!! :-) Have a great daayy!

6 0
3 years ago
Read 2 more answers
A man wishes to row the shortest possible distance from north to south across a river which is flowing at 2 km/hr from the east.
sweet-ann [11.9K]

From the diagram we have that

sin\theta = \frac{2}{4}

\theta = sin^{-1} (\frac{1}{2})

\theta = 30\°

Therefore the direction is 30° from east of south

8 0
3 years ago
A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic e
balandron [24]

Answer:

0.00001 J

Explanation:

k.e =  \frac{1}{2} m {v}^{2}  \\  =  \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2}  \\  = 0.00001j

3 0
3 years ago
In Trial II, the same spring is used as in Trial I. Let us use this information to find the suspended mass in Trial II. Use 0.51
Masteriza [31]

Answer:

M_2=0.79kg

Explanation:

From the question we are told that:

Period T=0.517s

Trial 1

Spring constant \mu=117N/m

Period T_1=0.37

Mass m=0.400kg

Trial 2

Period T_2=0.52

Generally the equation for Spring Constant  is mathematically given by

\mu=\frac{4 \pi^2 M}{T^2}

Since

\mu _1=\mu_2

Therefore

\frac{4 \pi^2 M_1}{T_1^2}=\frac{4 \pi^2 M_2}{T_2^2}

M_2=M_1*(\frac{T_2}{T_1})^2

M_2=0.400*(\frac{0.52}{0.37}})^2

M_2=0.79kg

5 0
3 years ago
A machine gear consists of 0.10 kg of iron and 0.16 kg of copper.
Natali5045456 [20]

Answer:

option (c)

Explanation:

mass of iron = 0.10 kg

mass of copper = 0.16 kg

rise in temperature, ΔT = 35°C

specific heat of iron = 450 J/kg°C

specific heat of copper = 390 J/kg°C

Heat by iron (H1) = mass of iron x specific heat of iron x ΔT

H1 = 0.10 x 450 x 35 = 1575 J

Heat by copper (H2) = mass of copper x specific heat of copper x ΔT

H1 = 0.16 x 390 x 35 = 2184 J

Total heat H = H1 + H2

H = 1575 + 2184 = 3759 J

by rounding off

H = 4000 J

6 0
3 years ago
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