Answer:

Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to infer this problem is about the application of the Gay-Lussac's gas law to relate the initial and final pressure and temperature as shown below:

Thus, solving for the final pressure, P2, and using the temperatures in Kelvins, we obtain:

Regards!
Answer:
12 moles of propane.
Explanation:
From the question given above, the following data were obtained:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 127 °C
Number of mole (n) =?
Next, we shall convert 127 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 127 °C
T(K) = 127 + 273
T(K) = 400 K
Finally, we shall determine the number of mole of propane gas in the container. This can be obtained as follow:
Volume (V) = 216 L
Pressure (P) = 184.8 KPa
Temperature (T) = 400 K
Gas constant (R) = 8.314 L.KPa/Kmol
Number of mole (n) =?
PV = nRT
184.8 × 216 = n × 8.314 × 400
39916.8 = n × 3325.6
Divide both side by 3325.6
n = 39916.8 / 3325.6
n = 12 moles
Thus, 12 moles of propane is present in the cylinder
Answer:
3,200 joules
Explanation:
q = mcΔT = (250.0 g)(0.128 j/g°C)(100°C -25°C) = 3,200 joules
Answer:
A ground wire helps those positive charges get to the ground in a safe, direct and controlled way, where they can be discharged without the risk of electrical shock or fire. Shock Absorber Excess electrical charges are common in any home.
Explanation:
:3