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aliya0001 [1]
3 years ago
8

If a sample of matter cannot be separated by physical means, what can be said with certainty about that sample?

Chemistry
1 answer:
julsineya [31]3 years ago
6 0

Answer:

b an element

Explanation:

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Starting with benzene as the only aromatic compound
Kipish [7]

Answer: The reaction of benzene with concentrated sulfuric acid at room temperature produces benzenesulfonic acid. The reaction forms a stable carbocation. SO3 being the electrophile

Explanation:

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3 years ago
What is the molar mass of sodium phosphate, Na3PO4?
baherus [9]

Answer:

164g

Explanation:

3×23+31+16×4

≈69+31+64

≈164.0 g

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Classify the bonds formed between each pair as ionic, polar covalent, or nonpolar covalent based solely on each element's positi
Amanda [17]
<span>you have to find the differences of electronegativity for the atoms joined by the bond. if their diff is <0.4,
then it's non-polar if it's between 0.4 to 1.7
then it's polar 1.7 and up it's ionic Electronegativity values can be found on most periodic tables.</span>
5 0
2 years ago
Your dad is working on creating a brick border for the lake in your backyard each brick has a mass of 100 g and a volume of 20 c
wel

Answer:

5000kg/m³

Explanation:

density=mass/volume

d=m/v

d=100/20

=5g/cm³

g/cm³*1000=kg/m³

5g/m³*1000=5000kg/m³

4 0
2 years ago
Read 2 more answers
2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)
Paha777 [63]
<h3>Answer:</h3>

16.7 g H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

  • Reading a Periodic Table
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                               \displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})
  2. Multiply/Divide:                 \displaystyle 16.6685 \ g \ H_2O

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

16.6685 g H₂O ≈ 16.7 g H₂O

6 0
2 years ago
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