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Olegator [25]
2 years ago
5

Which cup has more thermal energy?

Chemistry
1 answer:
dybincka [34]2 years ago
5 0

<em>Question: </em><em>Which cup has more thermal energy?</em>

<em>                   A. 2 liter cup of milk</em>

<em>                   B. 1 liter cup of milk</em>

<em>Answer: A. 2 liter cup of milk</em>

<em />

<em>Explanation:</em>

We have milk in both of the containers. The milk in both containers is the same temperature, so we will have to measure the amount of molecules. The amount of molecules makes it warmer, and if it is warmer, that is more energy. 2 liters have more thermal energy than 1 liter, because it has more molecules.

Our answer is 2 liter cup of milk.

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How many grams of chlorine gas are present in a 150. liter cylinder of chlorine held at a pressure of 1.00 atm and 0. °C? Group
OlgaM077 [116]

Answer:

474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C

Explanation:

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:  

P*V = n*R*T

where P is the gas pressure, V is the volume that occupies, T is its temperature, R is the ideal gas constant, and n is the number of moles of the gas.

In this case:

  • P= 1.00 atm
  • V= 150 L
  • n= ?
  • R= 0.082 \frac{atm*L}{mol*K}
  • T= 0 C= 273 K

Replacing:

1.00 atm* 150 L= n*0.08206 \frac{atm*L}{mol*K} *273 K

Solving:

n=\frac{1.00 atm* 150 L}{0.08206 \frac{atm*L}{mol*K}*273 K}

n= 6.69 moles

Being Cl= 35.45 g/mole, the molar mass of chlorine gas is:

Cl₂=2*35.45 g/mole= 70.9 g/mole

So if 1 mole has 70.9 grams, 6.69 moles of the gas, how much mass does it have?

mass=\frac{6.69 moles*70.9 grams}{1 mole}

mass= 474.321 grams ≅ 474 grams

<u><em>474 grams of chlorine gas are present in a 150 liter cylinder of chlorine held at a pressure of 1.00 atm and 0 °C</em></u>

4 0
2 years ago
How do flowering plants depend on other living things in order to reproduce?
Rufina [12.5K]

Answer:

They depend on people to water them and make sure they are by a window for sunlight

Explanation:

plants cant do these things by themselves

5 0
2 years ago
Read 2 more answers
The molarity of concentrated acetic acid is 17.45 M. When acetic acid is diluted in water it is commonly called vinegar with a m
Sladkaya [172]

M1 = 17.45 M

M2 = 0.83 M

V2 = 250 ml

M1. V1= M2. V2

V1 = (M2. V2)/M1 = (0.83× 250)/ 17.45= 11.89 ml

7 0
2 years ago
Find the volume of an object that has a density 0f 3.14g/mL and a mass of 87.3g
pav-90 [236]

Answer:

<h3>The answer is 27.80 mL</h3>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density}  \\

From the question

mass = 87.3 g

density = 3.14 g/mL

We have

volume =  \frac{87.3}{3.14}  \\  = 27.8025477...

We have the final answer as

<h3>27.80 mL</h3>

Hope this helps you

3 0
3 years ago
Be sure to answer all parts. Sulfur dioxide is released in the combustion of coal. Scrubbers use lime slurries of calcium hydrox
scoray [572]

<u>Answer:</u> The balanced chemical equation is written below and \Delta S^o for the reaction is -160.6 J/K

<u>Explanation:</u>

When calcium hydroxide reacts with sulfur dioxide, it leads to the formation of calcium sulfate and water molecule.

The chemical equation for the reaction of calcium hydroxide and sulfur dioxide follows:

Ca(OH)_2(s)+SO_2(g)\rightarrow CaSO_3(s)+H_2O(l)

To calculate the entropy change of the reaction, we use the equation:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{products}]-\sum [n\times \Delta S^o_{reactants}]

For the given reaction:

\Delta S^o_{rxn}=[(1\times \Delta S^o_{CaSO_3(s)})+(1\times \Delta S^o_{H_2O(l)})]-[(1\times \Delta S^o_{Ca(OH)_2(s)})+(1\times \Delta S^o_{SO_2(g)})]

Taking the standard entropy change values:

\Delta S^o_{CaSO_3(s)}=101.4Jmol^{-1}K^{-1}\\\Delta S^o_{H_2O(l)}=69.9Jmol^{-1}K^{-1}\\\Delta S^o_{Ca(OH)_2(s)}=83.4Jmol^{-1}K^{-1}\\\Delta S^o_{SO_2(g)}=248.5Jmol^{-1}K^{-1}

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(1\times (101.4))+(1\times (69.9))]-[(1\times (83.4))+(1\times (248.5))]\\\\\Delta S^o_{rxn}=-160.6J/K

Hence, the balanced chemical equation is written above and \Delta S^o for the reaction is -160.6 J/K

3 0
2 years ago
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