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Sati [7]
4 years ago
15

Halp!

Chemistry
1 answer:
Nadya [2.5K]4 years ago
5 0

Answer:

One with mass 0.52kg will have higher acceleration.

Explanation:

We know that

F = m x a

As we can see, for a constant value of F , for a body having more mass will have less acceleration and a body having less mass will have more acceleration ( Inversely proportional when force applied is constant).

Therefore lesser mass body will have more acceleration.

Hence, <em>0.52 kg body will have more acceleration. </em>

Verification :

F = ma

For 0.52kg:

a= F / m = 26 / 0.52 = 50 m/s²

For 0.78kg:

a= F/m = 26 / 0.78 = 33.3 m/s²

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Due to the temperature of the surrounding earth
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4 years ago
Using the word bank explain why increasing the temperature increases the rate of reaction​
katrin2010 [14]

Answer:Increasing the temperature increases reaction rates because of the disproportionately large increase in the number of high energy collisions. It is only these collisions (possessing at least the activation energy for the reaction) which result in a reaction.

Explanation:

5 0
3 years ago
Use the table on the right to calculate each required quantity
ValentinkaMS [17]

(1) The quantity of heat required to melt 175 g Cu is 35.88 kJ.

(2) The substance that releases 21.2 kJ of energy when 1.42 mol of it freezes is iron.

<h3>What is heat of fusion?</h3>

Heat of fusion is the energy required to melt 1 mole of a substance.

<h3>What is heat of vaporization?</h3>

The heat energy required to vaporize 1 mole of a substance has been heat of vaporization.

Heat of fusion of copper (Cu) is given as 13 kJ/mol

Number of  moles of 175 g of copper = 175/63.5 = 2.76 moles

Q = nΔH

Q = 2.76 mol  x 13 kJ/mol = 35.88 kJ

Thus, the quantity of heat required to melt 175 g Cu is 35.88 kJ.

<h3>Heat of fusion of the substance</h3>

ΔH(fus) = Q/n

where;

  • n is number of moles
  • Q is quantity of heat released

ΔH(fus) = 21.2 kJ / 1.42 mol

ΔH(fus) = 14.93 kJ/mol

From the table the substance with latent heat of fusion of 14.9 kJ/mol is iron.

Thus, the substance that releases 21.2 kJ of energy when 1.42 mol of it freezes is iron.

Learn more heat of fusion here: brainly.com/question/87248

#SPJ1

3 0
2 years ago
How much water should be added to 85 mL of 0.45 M HCI to reduce the concentration to 0.20 M?
valkas [14]

Answer:

106.25 mL

Explanation:

For this, we can use

C1×V1=C2×V2

C1 = 0.45

V1 = 85

C2= 0.20

V2= ?

0.45 × 85 = 0.20 × V2

V2= (0.45 × 85)/0.20

V2=191.25mL

To find the amount of water added, subtract V1 from V2

191.25 - 85 =106.25mL

8 0
4 years ago
Classify each of these reactions. Ba ( ClO 3 ) 2 ( s ) ⟶ BaCl 2 ( s ) + 3 O 2 ( g ) acid–base neutralization precipitation redox
Blababa [14]

Answer:

Ba(ClO₃)₂ (s) ⟶ BaCl₂(s) + 3O₂ (g)   REDOX

2 NaCl (aq) + K₂S (aq) ⟶ Na₂S (aq) + 2 KCl (aq)        NONE

CaO (s) + CO₂ (g) ⟶ CaCO₃(s) NONE

KOH (aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH (s)  PRECIPITATION

Ba (OH)₂(aq) + 2 HNO₂(aq) ⟶ Ba (NO₂)₂(aq) + 2 H₂O (l)  NEUTRALIZATION

Explanation:

Redox reaction involves the oxidation states. The oxidation state from an element decreases and the oxidation state from other element increases.

It is called redox because one element reduces and the other oxidizes.

Neutralization reaction occurs when an acid and a base react, to produce water an a determined salt.

Precipitation reaction can be produced when a solid is formed as the reactants react.

Ba(ClO₃)₂ (s) ⟶ BaCl₂(s) + 3O₂ (g)   REDOX

Cl changes the oxidation state from 5 to -1  (reduction)

O changes the oxidation state from -2 to 0 (oxidation)

2 NaCl (aq) + K₂S (aq) ⟶ Na₂S (aq) + 2 KCl (aq)        NONE

CaO (s) + CO₂ (g) ⟶ CaCO₃(s) NONE

KOH (aq) + AgNO₃(aq) ⟶ KNO₃(aq) + AgOH (s)  PRECIPITATION

Ba (OH)₂(aq) + 2 HNO₂( aq ) ⟶ Ba (NO₂)₂(aq) + 2 H₂O (l)  NEUTRALIZATION

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