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3 years ago

How many moles of methane will react to form 3.2 moles of carbon dioxide?

Chemistry

1 answer:

Hunter-Best [27]3 years ago

6 0

Answer:

3.2 moles

Explanation:

First, we'll begin by writing a balanced equation for the Combustion of methane to produce carbon dioxide. This is illustrated below:

CH4 + 2O2 —> CO2 + 2H2O

From the balanced equation above,

1 mole of methane (CH4) reacted to produced 1 mole of carbon dioxide (CO2).

Therefore, 3.2 moles of methane (CH4) will react to produce 3.2 moles of carbon dioxide (CO2).

From the illustration above, 3.2 moles of methane is needed to produce 3.2 moles of carbon dioxide.

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3 years ago

Phenolphthalein has a pKa of 9.7 and is colorless in its acid form and pink in its basic form. calculate [In-}/{HIn} for the fol

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Answer:

1.58x10⁻⁵

2.51x10⁻⁸

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Explanation:

Phenolphthalein acts like a weak acid, so in aqueous solution, it has an acid form HIn, and the conjugate base In-, and the pH of it can be calculated by the Handerson-Halsebach equation:

pH = pKa + log[In-]/[HIn]

pKa = -logKa, and Ka is the equilibrium constant of the dissociation of the acid. [X] is the concentrantion of X. Thus,

i) pH = 4.9

4.9 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = - 4.8

[In-]/[HIn] = $10^{-4.8}$

[In-]/[HIn] = 1.58x10⁻⁵

ii) pH = 2.1

2.1 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -7.6

[In-]/[HIn] = $10^{-7.6}$

[In-]/[HIn] = 2.51x10⁻⁸

iii) pH = 7.8

7.8 = 9.7 + log[In-]/[HIn]

log[In-]/[HIn] = -1.9

[In-]/[HIn] = $10^{-1.9}$

[In-]/[HIn] = 0.0126

iv) pH = 11.5

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log[In-]/[HIn] = 1.8

[In-]/[HIn] = $10^{1.8}$

[In-]/[HIn] = 63.10

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3 years ago