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katen-ka-za [31]
4 years ago
15

MgX2 Very low density Highly reactive Diatomic Using the periodic table, determine which element these characteristics MOST LIKE

LY describe. A)fluorine B)iodine C)oxygen D)sodium
Chemistry
2 answers:
snow_tiger [21]4 years ago
6 0

Answer:

Flourine

Explanation:

The answer is Flourine i guessed and got it right!

photoshop1234 [79]4 years ago
3 0
Oxygen, fluorine and iodine are diatomic elements. Flourine is more reactive than the other two because it is the closest away to filling its outer layer of electrons and becoming stable like a noble gas.
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What is e cell (in units of volts) for a galvanic cell constructed from barium and manganese electrodes?
gulaghasi [49]

Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.

Explanation:

When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:

Mn2+(aq) + 2e-⟶ Mn(s)                                             E1 = −1.185

Ba2+(aq) + 2e-⟶ Ba(s)                                                 E2 = −2.912

By considering the above two reactions, the standard electrode potential can be calculated.

The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts

What is standard electrode potential?

Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.

To know more about galvanic cell, please visit:

brainly.com/question/13031093

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3 0
2 years ago
Consider the reaction 2CuCl2 + 4KI → 2CuI + 4KCl + I2. If 4 moles of CuCl2 react with 4 moles of KI, what is the limiting reacta
Tatiana [17]

Explanation:

here's the answer to your question

4 0
3 years ago
Prescribed burns are used to _______. a. clear out undergrowth b. prevent larger forest fires c. manage forests d. all of the ab
Firlakuza [10]
D) All Of The Above 
I think this is right.
5 0
4 years ago
Read 2 more answers
The half-life of bismuth-210, 210bi, is 5 days. (a) if a sample has a mass of 184 mg, find the amount remaining after 15 days.
ASHA 777 [7]

Answer:- 23.0 mg

Solution:- Radioactive decay obeys first order kinetics and the first order kinetics equation is:

lnN=-kt+lnN_0

where, N_0 is the initial amount of radioactive substance and N is it's amount after time t. k is the decay constant.

From given information, Original amount, N_0 of the radioactive substance is 184 mg and we are asked to calculate the amount N after 15 days. It means, t = 15 days

Half life is given as 5 days. From the half life, we could calculate the decay constant k using the equation:

k=\frac{0.693}{t_1_/_2}

where, t_1_/_2 is the symbol for half life. let's plug in the value of half like to calculate k:

k=\frac{0.693}{5days}

k=0.1386day^-^1

Let's plug in the values in the first order kinetics equation and solve it for N:

lnN=-0.1386day^-^1(15days)+ln184mg

lnN=-2.079+5.215

lnN = 3.136

N=e^3^.^1^3^6

N = 23.0 mg

So, 23.0 mg of Bi-210 would be remaining after 15 days.

3 0
4 years ago
Stephans mother cuts a twig from a rose bush and plants it in the soil. After a few days, Stephan observes a new plant growing.
mixer [17]

Answer:

This depict that the growth of the new plant has taken place due to asexual form of reproduction.

Explanation:

A procedure in which new offspring is generated from a single parent without involving sex cells or gametes is known as asexual reproduction. One of the asexual forms of reproduction in plants is the artificial propagation of plants. The three general procedures of artificial propagation of plants are layering, cuttings, and grafting.  

In cutting, a novel plant is developed by incising a small section of a plant that can be anything comprising bud on it. This section of the plant is then watered and grown into soil, and after some days a new plant begins to grow.  

8 0
3 years ago
Read 2 more answers
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