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4 years ago

When HCl is added to water, the [H3O+] = 0.6 M. What is the [OH-]?

Chemistry

1 answer:

makkiz [27]4 years ago

3 0

Answer:

The answer is

Explanation:

To find the [OH-] we must first find the pH and the pOH of the solution

That's

pH + pOH = 14

pOH = 14 - pH

To find the pH we use the formula

pH = -log [H3O+]

From the question

[H3O+] = 0.6 M

pH = - log 0.6

pH = 0.22

pOH = 14 - 0.22

pOH = 13.78

We can now find the [OH -] in the solution using the formula

pOH = - log [OH-]

13.78 = - log [OH-]

Find the antilog of both sides

We have the final answer as

Hope this helps you

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<u>Answer: </u>One isotope has a percentage abundance of 75.75 % and the percentage abundance of another isotope is 24.24%.

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For Chlorine-35 isotope:

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The formula for the calculation of average atomic mass is given by:

$\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i$

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Converting these two fractional abundances into percentage abundances by multiplying it with 100.

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3 years ago

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Answer:

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Since the concentration of the hydronium ion= 2.3 X 10^-7 M

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[H3O^+] [OH^-] = 1 * 10^-14

[H3O^+] = concentration of the hydronium ion

[OH^-] = concentration of the hydroxide ion

So;

[OH^-] =1 * 10^-14/[ H3O^+]

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