Question

When HCl is added to water, the [H3O+] = 0.6 M. What is the [OH-]?

Answer 1

Answer:

The answer is

[OH-] = 1.66 × 10^-14 M

Explanation:

To find the [OH-] we must first find the pH and the pOH of the solution

That's

pH + pOH = 14

pOH = 14 - pH

To find the pH we use the formula

pH = -log [H3O+]

From the question

[H3O+] = 0.6 M

pH = - log 0.6

pH = 0.22

pOH = 14 - 0.22

pOH = 13.78

We can now find the [OH -] in the solution using the formula

pOH = - log [OH-]

13.78 = - log [OH-]

Find the antilog of both sides

We have the final answer as

[OH-] = 1.66 × 10^-14 M

Hope this helps you