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Alik [6]
4 years ago
8

In a salt solution, what happens to sodium and chloride ions?

Chemistry
1 answer:
iVinArrow [24]4 years ago
4 0
<span>In a salt solution (a solution of water (H2O) and Salt, chemical formula NaCl), the positively charged Hydrogen atoms from water form bonds with the negatively charged Chloride atoms of Salt (which is the formulate NaCl), and the negatively charged oxygen atom of water (one atom per water molecule) form a bond with the positively charged Sodium ions (Na) of salt.</span>
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julsineya [31]

Answer:

The mass of 10 cm³of a 0.4 g/dm³ solution of sodium carbonate is 0.004 grams

Explanation:

The question is with regards to density calculations

The density of the given sodium carbonate solution, ρ = 0.4 g/dm³

The volume of the given solution of sodium carbonate, V = 10 cm³ = 0.01 dm³

Density \ of \ an \ object, \rho  = \dfrac{The \ mass \ of \ the \ object, \ m }{\ The \ volume \ of \ the \ object, \ V }

\rho = \dfrac{m}{V}

Therefore, we have;

The \ Density \ of \ the \ sodium \ carbonate, \ \rho  = 0.4 \ g/dm^3 =  \dfrac{m }{ 0.01 \ dm^3 }

The mass, "m", of the sodium carbonate in  = ρ×V = 0.4 g/dm³ × 0.01 dm³ = 0.004 g

The mass of 10 cm³ (10 cm³ = 0.01 dm³) of a 0.4 g/dm³ solution of sodium carbonate, m = 0.004 g.

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