Question

The normal stress at gage H calculated in Part 1 includes four components: an axial component due to load P, σaxial, P, a bending component due to load P, σbend, P, an axial component due to load Q, σaxial, Q, and a bending component due to load Q, σbend, Q. Calculate σaxial, P and σbend,P. Use the sign convention for normal stresses. If a normal stress component is tension, it is positive, and if it is compression, it is negative.

Answer 1

Answer:

hello your question has some missing information attached to the answer is the missing component

Answer : αaxial,p = -6.034 ksi ( compressive )

             αbend,p = 19.648 ksi ( tensile )

Explanation:

αaxial, p = $\frac{-p}{A}$   equation 1

αbend, p = $\frac{(P*A)*\frac{d}{2} }{I_{z} }$ equation 2

P = load = 35 kips

A = area of column = 5.8 $in^{2}$

d = column cross section depth = 9.5 in

$I_{Z}$ = 55.0 $in^{4}$

Hence equation 1 becomes

αaxial,p = -35 / 5.8 = - 6.034 ksi ( compressive )

equation 2 becomes

αbend, p = $\frac{(35*6.5)(\frac{9.2}{2}) }{55}$ = + 19.648 ksi ( tensile )