All of these are uses of microwaves except...

Assume a function requires 20 lines of machine code and will be called 10 times in the main program. You can choose to implement

Volgvan

Answer:

"Macro Instruction"

Explanation:

A macro definition is a rule or pattern that specifies how a certain input sequence should be mapped to a replacement output sequence according to a defined procedure. The mapping process that instantiates a macro use into a specific sequence is known as macro expansion.

It is a series of commands and actions that can be stored and run whenever you need to perform the task. You can record or build a macro and then run it to automatically repeat that series of steps or actions.

7 0

3 years ago

Describe the algorithm you use for looking up a person’s telephone number in the phone book. The input is person’s name; the out

Stella [2.4K]

Answer:

The Algorithm for finding a number from a phone book with the person's name as the input and the phone number as output is as follows:

1. Try to remember the name, i.e last name first and first name last, Also make sure you get the spelling right.

2. Using the first letter of the last name, locate the appropriate alphabetical section in which the name should appear.

3. Using the second letter of the last name, find the subsection of first and second letters combined, in the appropriate order, in which the name should appear. (If the last name consists of only two letters, find the appropriate first name.)

4. Using the third letter, find the possible names in a subsection of the first three letters in the correct order. Continue this step with x+1 letters of the name until you have a subsection of names exactly matching the last name of the person whose number you are trying to locate. (x is the number of letters used in the previous step, consistently.) If there is only one of the last name, (check for duplicates) identify the number, and return phone number information.

5. Begin the second step using the first letter of the first name, but limit the section to only those exactly matching the last name. Continue to step 4, again focusing on the first name only within the set of exactly matching last names.

6. When both first and last name match the name you are locating, check for duplicates. IF there are no duplicates, return phone number information.

Explanation:

People's names are generally arranged in phone books in alphabetical order by the last name of the person. The first name of the person is listed after the last name so that people of the same last name can be differentiated.

7 0

4 years ago

Read 2 more answers

The 2-lb block is released from rest at A and slides down along the smooth cylindrical surface. Of the attached spring has a sti

MA_775_DIABLO [31]

Answer:

L = 4.574 ft

Explanation:

Given:

- The weight of the block W = 2 lb

- The initial velocity of the block v_i = 0

- The stiffness of the spring k = 2 lb/ft

- The radius of the cylindrical surface r = 2 ft

Find:

Determine its unstretched length so that it does not allow the block to leave the surface until θ= 60°.

Solution:

- Compute the velocity of the block at θ= 60°. Use Newton's second equation of motion in direction normal to the surface.

F_n = m*a_n

Where, a_n is the centripetal acceleration or normal component of acceleration as follows:

a_n = v^2_2 / r

- Substitute:

F_n = m*v^2_2 / r

Where, F_n normal force acting on block by the surface is:

F_n = W*cos(θ)

- Substitute:

W*cos(θ) = m*v^2_2 / r

v_2 = sqrt ( r*g*cos(θ) )

- Plug in the values:

v^2_2 = 2*32.2*cos(60)

v^2_2 = 32.2 (ft/s)^2

- Apply the conservation of energy between points A and B where θ= 60° :

T_A + V_A = T_B + V_B

Where,

T_A : Kinetic energy of the block at inital position = 0

V_A: potential energy of the block inital position

V_A = 0.5*k*x_A^2

x_A = 2*pi - L ..... ( L is the original length )

V_A = 0.5*2*(2*pi - L)^2 =(2*pi - L)^2

T_B = 0.5*W/g*v_2^2 = 0.5*2 / 32.2 *32.2 = 1

V_B = 0.5*k*x_B^2 + W*2*cos(60)

x_B = 2*0.75*pi - L ..... ( L is the original length )

V_B = 0.5*2*(1.5*pi - L)^2 + 2*1 = 2 + ( 1.5*pi - L )^2

- Input the respective energies back in to the conservation expression:

0 + (2*pi - L)^2 = 1 + 2 + ( 1.5*pi - L )^2

4pi^2 - 4*pi*L + L^2 = 3 + 2.25*pi^2 - 3*pi*L + L^2

pi*L = 1.75*pi^2 - 3

L = 4.574 ft

3 0

3 years ago

A cylindrical bar of steel 10.1 mm (0.3976 in.) in diameter is to be deformed elastically by application of a force along the ba

Nina [5.8K]

Answer:

given d= 10.2x10-3m

change in diameter d' =3.4x10-6 m

elastic modulus=207x109pa

1/m=0.30

we know that stress/strain=E

but poissons ratio 1/m = lateral starin/longitudinal starin

0.3= (d'/d)/(L'/L)

L'/L = 3.4x10-6/(0.3x10.2x10-3)

= 1.11*10-3

E= (f/A)/(L'/L)

force f= E*A*(L'/L)

f =(1.11*10-3)*207*109*(3.1415*(10.2*10-3)2)/4

= 18775.2N =18.775KN

Explanation:

The force that produce an elastic reduction is 18.775KN

4 0

3 years ago

A precision miling machince wighing 1000lb is supported on a rubber mount. The force deflection relationship of the rubber mount

Alisiya [41]

Answer:

0.2846 in

Explanation:

The static equilibrium position of the rubber mount ( $x^*$ ), under the weight of the milling machine, can be determined from:

$1000=3500(x^*)+ 55(x^*)^3\\\\55(x^*)^3+ 3500x^*-1000=0\\\\Solving\ for\ the\ roots\ using \ a \ calculator\ or\ matlab\ gives:\\ \\x^*_1=0.28535\\x^*_2=-0.14267+7.89107i\\x^*_3=-0.14267-7.89107i\\\\We\ are\ using\ the \ real\ root\ which\ is\ x^*_1=0.28535\\$

$k=\frac{dF}{dx}|_{x^*}\\ \\k=\frac{d}{dx}(3500x+55x^3)|_{x^*}\\\\k=3500+165x^2|_{x^*}\\\\k=3500+165(x^*)^2\\\\k=3500+165(0.28535)^2=3513.435\ lb/in$

The static equilibrium position is at:

$x=\frac{F}{k}=\frac{1000}{3513.435} =0.2846\ in$

8 0

3 years ago