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asambeis [7]
3 years ago
5

Everfi futuresmart module 6 retirement pie chart

Engineering
2 answers:
Arada [10]3 years ago
8 0

Answer:

Bonds: 40%

Mutual fund: 25%

Stock: 20%

Savings account: 15%

Explanation:

Katarina [22]3 years ago
3 0

Answer:

good luck

Explanation:

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Help I will brainliest
ValentinkaMS [17]

Answer:

hacking?

Explanation:

jsd

3 0
3 years ago
The rectangular frame is composed of four perimeter two-force members and two cables AC and BD which are incapable of supporting
Rama09 [41]

Answer:

Your question is lacking some information attached is the missing part and the solution

A) AB = AD = BD = 0, BC = LC

    AC = \frac{5L}{3}T, CD = \frac{4L}{3} C

B) AB = AD = BC = BD = 0

   AC = \frac{5L}{3} T, CD = \frac{4L}{3} C

Explanation:

A) Forces in all members due to the load L in position A

assuming that BD goes slack from an inspection of Joint B

AB = 0 and BC = LC from Joint D, AD = 0 and CD = 4L/3 C

B) steps to arrive to the answer is attached below

AB = AD = BC = BD = 0

AC = \frac{5L}{3} T,  CD = \frac{4L}{3}C

7 0
4 years ago
Technician A says inspecting the operation of the automatic emergency brake system helps determine whether the spring brakes wil
laila [671]

Answer: Both Technicians

Explanation:

When testing a spring break it is advisable to Step on and off the brake, with the engine off, the parking brake knob is expected to pop out when air pressure falls between 20-40 psi.

Go under the vehicle and pull the spring brakes.

Turn on the engine back and pump the brake pedal down to the floor. To test the spring breaks

8 0
3 years ago
How many ( 1/8") in one inch?
Anna35 [415]

Answer:

1 inch

Explanation:

There for there are 8 1/8 inch that make up 1 inch so the answer is 1 inch

4 0
3 years ago
Read 2 more answers
Assume that a surface-grinding operation is being carried out under the following conditions: D = 250 mm, d 0.1 mm, ys 0.5 m/s a
Misha Larkins [42]

Answer:

modify temperature is lower than by the 0.196 %

Explanation:

given data

D = 250 mm

d = 0.1 mm

v = 0.5 m/s

V = 50 m/s

D = 150 mm

d = 0.1 mm

v = 0.3 m/s

V = 25 m/s

solution

first we get here initial coating condition for temperature change ΔT is

ΔT = A \times D^{1/4} \times d^{3/4}\times \frac{V}{v}^{1/2}    ...............1

put here value for both condition

ΔT = A \times 250^{1/4} \times 0.1^{3/4}\times \frac{50}{0.5}^{1/2}  

ΔT = 7.07 A      ......................2

and

ΔT = A \times 150^{1/4} \times 0.1^{3/4}\times \frac{25}{0.3}^{1/2}  

ΔT = 5.68 A       .......................3

so here percentage change is

percentage change = \frac{5.68 A-7.07 A }{7.07 A }  

percentage change  = - 0.196

so that modify temperature is lower than by the 0.196 %

5 0
3 years ago
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