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3 years ago

Everfi futuresmart module 6 retirement pie chart

Engineering

2 answers:

Arada [10]3 years ago

8 0

Answer:

Bonds: 40%

Mutual fund: 25%

Stock: 20%

Savings account: 15%

Explanation:

Katarina [22]3 years ago

3 0

Answer:

good luck

Explanation:

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2. Controlled-access highways permit traffic to enter them only from

Ainat [17]

Answer:

True

Explanation:

A controlled access high way is a type of high way that access into it is controlled and restricted. It restricts the access to the highway from driveways and only allows traffic to come into through them from interchanges.

A controlled access high way is made up of 4 lanes . A controlled access high way does not allow or permit crossing because vehicles pass through this highways at a very high speed. Traffic is always high or at it's maximum on a controlled access highway.

A controlled access highway lacks the presence of traffic lights.

7 0

3 years ago

A good attitude toward blank means believing that the proper attitude and habits are extremely important

Serggg [28]

Answer:

the blank = life

Explanation:

:) happy holidays!

6 0

3 years ago

The specific gravity of a substance that has mass of 10 kg and occupies a volume of 0.02 m^3 is a) 0.5 b) 1.5 c) 2.5 d) 3.5 e) n

zhuklara [117]

Answer:

Specific gravity is 0.5 so option (a) is correct option

Explanation:

We have given mass of substance m =10 kg

Volume $V=0.02m^3$

Density of substance is given by $Density\ d=\frac{mass}{volume}=\frac{10}{0.02}=500kg/m^3$

Specific gravity is given by $specific\ gravity=\frac{density\ of\ substance}{density\ f\ water}=\frac{500}{1000}=0.5$

So option (a) is correct option

5 0

3 years ago

The density of a liquid is to be determined by an old 1-cm-diameter cylindrical hydrometer whose division marks are completely w

Simora [160]

Answer:

1064.8 kg/m³

Explanation:

Weight of the hydrometer = ρghA where ρ is the density, g is acceleration due to gravity, h is the submerged height and A is the cross sectional area.

W in water = ρwghwA

W in liquid = (ρliq)g hliq A where the cross sectional area is constant

W in water = W in liquid

(ρw)ghwA = (ρliq)g hliq A where ρw is density of water, ρliq is the density of liquid and hw and hliq are the heights of the liquid and that water. g acceleration due to gravity cancel on both sides as well as the constant A

pliq = $\frac{hw}{hliq}$ × 1000 kg /m³ ( density of water) =( $\frac{23}{23-1.4}$ ) × 1000 = 1064.8 kg/m³