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Answer:
8. A boat, cars, airplanes
9. It's safer to practice techniques on life sized models of human organs than practicing on an actual human. If you mess up on a model it doesn't matter, messing up on a human can put their life at risk.
The answer is [OH⁻] = 1 x 10⁻⁸.
To find OH⁻, divide the ionic product of water by [H₃O⁺] as :
<u>OH⁻ + H₃O⁺ = H₂O</u>
<u />
- [OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶
- [OH⁻] = 1 x 10⁻⁸
Answer:
See explanation below
Explanation:
To get this, we need to apply the general expression for half life decay:
N = N₀e(-λt) (1)
Where:
N and N₀ would be the final and innitial quantities, in this case, masses.
t: time required to decay
λ: factor related to half life
From the above expression we need λ and t. To get λ we use the following expression:
λ = t₁₂/ln2 (2)
And we have the value of half life, so, replacing we have:
λ = 8.04 / ln2 = 11.6
Now, we can replace in (1) and then, solve for t:
0.75 = 40 exp(-11.6t)
0.75 / 40 = exp(-11.6t)
ln(0.01875) = -11.6t
-3.9766 = -11.6t
t = -3.9766 / -11.6
<h2>
t = 0.34 days</h2><h2>
</h2>
Answer:
54.5%
Explanation:
The percentage composition of oxygen in C₆H₈O₆ can be obtained as follow:
Molar mass of C₆H₈O₆ = (12×6) + (8×1) + (16×6)
= 72 + 8 + 96
= 176 g/mol
Next, there are 6 oxygen atoms in C₆H₈O₆. Therefore the mass of oxygen in C₆H₈O₆ is:
Mass of Oxygen = 16 × 6 = 96 g
Finally, we shall determine the percentage composition of oxygen in C₆H₈O₆ as follow:
Percentage of oxygen =
Mass of Oxygen/mass of C₆H₈O₆ × 100
Percentage of oxygen = 96 / 176 × 100
Percentage of oxygen = 54.5%
Thus, the percentage composition of oxygen in C₆H₈O₆ is 54.5%.
