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galben [10]
3 years ago
11

He generic metal a forms an insoluble salt ab(s) and a complex ac5(aq). the equilibrium concentrations in a solution of ac5 were

found to be [a] = 0.100 m, [c] = 0.0380 m, and [ac5] = 0.100 m. determine the formation constant, kf, of ac5.
Chemistry
1 answer:
elena55 [62]3 years ago
7 0
Balanced chemical reaction: A + 5C ⇄ AC₅.
<span>[A] = 0.100 M; equilibrium concentration.
</span><span>[C] = 0.0380 M.
</span>[AC₅] = 0.100 M.
Kf = [AC₅] / ([A] · [C]⁵).
Kf = 0.100 M ÷ (0.100 M · (0.0380 M)⁵.
Kf = 12620658.54 = 1,26·10⁷.
<span>The formation constant can be calculated when </span>chemical equilibrium is reached, when the forward reaction rate is equal to the reverse reaction rate.
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What is the energy of a microwave photon that has a frequency of 9.86 x 1012 Hz?
BlackZzzverrR [31]

Answer:

6.533 × 10^-21J

Explanation:

The energy of the microwave photon can be calculated using:

E = hf

Where;

E = energy of photon (J)

h = Planck's constant (6.626 × 10^-34 J/s)

f = frequency (9.86 x 10^12 Hz)

Hence, E = hf

E = 6.626 × 10^-34 × 9.86 x 10^12

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The energy of the microwave photon is

6.533 × 10^-21J

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Cuales elementos tienen solo un electrón de valencia ​
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En el caso del sodio, la valencia es 1, ya que tiene un solo electrón de valencia, si pierde un electrón se queda con el último nivel completo.

Explanation:

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What conversion factor does a balanced chemical equation give you?
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3 years ago
a solution of KCl in water has a concentration of 0.243 M. The solution has a volume of 0.580 L. How many grams of KCl are prese
Novosadov [1.4K]

Answer:

10.5 g

Explanation:

Step 1: Given data

  • Molar concentration of the solution (C): 0.243 M
  • Volume of solution (V): 0.580 L

Step 2: Calculate the moles of solute (n)

Molarity is equal to the moles of solute divided by the liters of solution.

M = n/V

n = M × V

n = 0.243 mol/L × 0.580 L = 0.141 mol

Step 3: Calculate the mass corresponding to 0.141 moles of KCl

The molar mass of KCl is 74.55 g/mol.

0.141 mol × 74.55 g/mol = 10.5 g

8 0
2 years ago
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