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galben [10]
3 years ago
11

He generic metal a forms an insoluble salt ab(s) and a complex ac5(aq). the equilibrium concentrations in a solution of ac5 were

found to be [a] = 0.100 m, [c] = 0.0380 m, and [ac5] = 0.100 m. determine the formation constant, kf, of ac5.
Chemistry
1 answer:
elena55 [62]3 years ago
7 0
Balanced chemical reaction: A + 5C ⇄ AC₅.
<span>[A] = 0.100 M; equilibrium concentration.
</span><span>[C] = 0.0380 M.
</span>[AC₅] = 0.100 M.
Kf = [AC₅] / ([A] · [C]⁵).
Kf = 0.100 M ÷ (0.100 M · (0.0380 M)⁵.
Kf = 12620658.54 = 1,26·10⁷.
<span>The formation constant can be calculated when </span>chemical equilibrium is reached, when the forward reaction rate is equal to the reverse reaction rate.
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s2008m [1.1K]

Answer:

65.08 g.

Explanation:

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<em>2AlCl₃ + 3Br₂ → 2AlBr₃ + 3Cl₂,</em>

2.0 mole of AlCl₃ reacts with 3.0 mole of Br₂ to produce 2.0 mole of AlBr₃ and 3.0 mole of Cl₂.

  • Firstly, we need to calculate the no. of moles of 36.2 grams of AlCl₃:

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<u><em>Using cross multiplication:</em></u>

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0.2715 mol of AlCl₃ reacts with → ??? mole of Br₂.

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