Answer:
2.9 m
Explanation:
First find the time it takes to reach the floor.
y = y₀ + v₀ t + ½ at²
(0 m) = (1.6 m) + (0 m/s) t + ½ (-9.8 m/s²) t²
t = 0.571 s
Next, find the distance it travels in that time.
x = x₀ + v₀ t + ½ at²
x = (0 m) + (5.0 m/s) (0.571 s) + ½ (0 m/s²) (0.571 s)²
x = 2.86 m
Rounded to two significant figures, the marble travels 2.9 meters in the x direction.
Answer:height above ground at which projectile have velocity
0.5v is (0.0375v^2)
Explanation:
Using Vf = Vi - gt
Where Vf is final velocity
Vi is initial velocity
g is the acceleration due to gravity
t is the time taken
So, 0.5v = v - gt
t = 0.05v
Therefore height h = vt - 0.5gt^2
Subtitute t
h = 0.05v^2 - 0.0125v^2
h = 0.0375v^2
Answer:
the acceleration of the car is 1.167 m/s²
Explanation:
Given;
initial velocity of the race car, u = 5 m/s
final velocity of the race car, v = 12 m/s
time to finish the race, t = 6 s
The acceleration of the car is calculated as;
a = (v - u) / t
a = (12 - 5) / (6)
a = 1.167 m/s²
Therefore, the acceleration of the car is 1.167 m/s²
Answer: 1100 ft lb/s and 2 H.P
Explanation:
To calculate for the power developed in the elevator motor in ft.lb/s, we multiply the distance and the weight of the elevator and divide the product by the time.
Power = (10 ft)(2200 lb) / 20 s = 1100 ft.lb/s
Next, convert the calculated value to HP.
1100 ft.lb/s x (1 HP/ 550 ft.lb/s) = 2 HP
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