Answer:
11,100 N
Explanation:
Draw the car on the incline. Label the weight and normal forces. Call the direction normal to the incline y, and the direction parallel to the incline x.
If it helps, rotate the incline so that the surface of the incline is flat.
Use trigonometry to determine the components of the weight force. The y component of the weight is:
Wᵧ = mg cos θ
Wᵧ = (1150 kg) (9.8 m/s²) (cos 8.70°)
Wᵧ = 11,100 N
The mass on the spring is 0.86 kg
Explanation:
The period of a mass-spring system is given by the equation
where
m is the mass
k is the spring constant
In this problem, we have:
k = 88.7 N/m is the spring constant
The system makes 15 oscillations in 9.24 s: therefore, the period of the system is
Now we can re-arrange the first equation to solve for the mass:
Learn more about period:
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Answer:
Distance, d = 778.05 m
Explanation:
Given that,
Force acting on the car, F = 981 N
Mass of the car, m = 1550 kg
Initial speed of the car, v = 25 mi/h = 11.17 m/s
We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:
Let d is the distance covered by car. Using second equation of motion as :
So, the car will cover a distance of 778.05 meters.