Given 3a/(a+1)^2
To make the denominator a cube, you would have to multiply by 1 or (a+1)/(a+1)
yielding 3a(a+1)/(a+1)^3
(3a^2 + 3a) is the equivalent numerator
Answer:
C x 34 or 34c
Step-by-step explanation:
There isn't really a way to show work or really an answer unless you have a value for C but I hope this helped anyway.
So i think you gotta see where the point is ay and if it isnt rig
So we can call first number "n"
Then all five integers would be n, n+1, n+2, n+3, n+4
So sum of them would be 5n + 10 = 100
Now you can solve for n:
5n + 10 = 100
5n = 90
n = 18
Verify: 18 + 19 + 20 + 21 + 22 = 100. All good.
So answer is 18
18y + 9 = -12 + 18y
9=-12
I hope that’s right... I haven’t done this in ages
