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strojnjashka [21]
3 years ago
15

You record a %T of 85 from a Spec 20. This is equivalent to what absorbable level?

Chemistry
1 answer:
spayn [35]3 years ago
8 0
Can someone plzzzzzzzzzz help me
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How many grams of chlorine gas can be produced when 50.0 grams of aluminum chloride decompose? 2AlCl3→ 2Al + 3Cl2
lianna [129]

Answer:

Explanation:

Approx.

425

⋅

g

Explanation:

2

A

l

(

s

)

+

3

C

l

2

(

g

)

→

2

A

l

C

l

3

(

s

)

You have given a stoichiometrically balanced equation, so bravo.

The equation explicitly tells us that

54

⋅

g

of aluminum metal reacts with

6

×

35.45

⋅

g

C

l

2

gas to give

266.7

⋅

g

of

aluminum trichloride

hope this helps

6 0
3 years ago
Plants like the ones shown in the picture, that use seeds, flowers, or fruit for reproduction are A) flowering. B) invertebrates
tensa zangetsu [6.8K]

Plants like the ones shown in the picture, that use seeds, flowers, or fruit for reproduction are A) flowering.

The picture shows flowering plants that are using seeds, flowers or fruits and they are called flowering plant .

So the answer here is A) flowering.

Plants like the ones shown in the picture, that use seeds, flowers, or fruit for reproduction are A) flowering.

7 0
3 years ago
Read 2 more answers
An unknown solution has a pH of 7.2. Which of these chemicals is likely to cause the greatest decrease in the pH of the solution
prohojiy [21]

Answer:

HNO₃.

Explanation:

  • It is known that acids decrease the pH of the solution, while bases increase  the pH of the solution.

So, HF and HNO₃ decrease the pH of the solution as they produce H⁺ in the solution.

While, KOH and NH₃ increase the pH of the solution as they produce OH⁻ in the solution.

HNO₃ will decrease the pH of the solution greater than HF.

  • Because HNO₃ is strong acid that decomposes completely to produce H⁺ more than the same concentration of HF that is a weak acid which does not decomposed completely to produce H⁺.
7 0
3 years ago
A total of 25.0 mL of 0.150 M potassium hydroxide (KOH) was required to neutralize 15.0 mL of sulfuric acid (H2SO4) of unknown c
Kamila [148]
We are told that KOH is being used to completely neutral H₂SO₄ according to the following reaction:

KOH + H₂SO₄ → H₂O + KHSO₄

If KOH can completely neutralize H₂SO₄, then there must be an equal amount of moles of each as they are in a 1:1 ratio:

0.025 L x 0.150 mol/L = .00375 mol KOH

0.00375 mol KOH x 1 mole H₂SO₄/1 mole KOH = 0.00375 mol H₂SO₄

We are told we have 15 mL of H₂SO₄ initially, so now we can find the original concentration:

0.00375 mol / 0.015 L = 0.25 mol/L

The concentration of H₂SO₄ being neutralized is 0.25 M.
6 0
3 years ago
<
victus00 [196]

Answer:

This isotope has 59 electrons giving it a charge of -2.

Explanation:

To find this we have to understand isotope relates to the mass of the nucleus. This isotope has 59 electrons to counter the protons and give it a negative charge.

6 0
2 years ago
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