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insens350 [35]
3 years ago
9

Define the dead or void time in HPLC? Plzzz help I’m struggling

Chemistry
1 answer:
marysya [2.9K]3 years ago
7 0

Answer:

2 Answers. The column is filled with the carrier (liquid or gas) before the sample is injected. Thus if there is no interaction between the sample and the column, then the fastest that the sample can get to the detector is the dead time denoted by tM in the diagram.

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What is the potential energy of the bowling ball as it sits on top of the building?
Tju [1.3M]

Answer:

Potential energy is energy due to an object's height above the ground.

Potential energy = mass x gravity x height

Kinetic energy is energy due to the motion of the object.

Kinetic energy = 1/2 x mass x velocity²

8 0
3 years ago
An airplane model is an example of what type of model
Ksju [112]
TL;DR: The make of an aircraft is the name of the designer (for example, Boeing) and the model of an aircraft (also called the type) is the designation for the general design of the aircraft (for example, 737). It looks like "basic model" is just an older term for "model".
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3 years ago
Please help me with this question
vampirchik [111]

Remember that

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  • For being a bond ionic ∆E>1.8

#1

  • ∆EN=0.5

Carbon is present so it's covalent

#2

  • OH bond is also covalent

#3

  • P-H will hardly form a bond

#4

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#5

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7 0
1 year ago
Help me please!!!( ꈍᴗꈍ)​
Dahasolnce [82]

Answer:

<h3>Which of the following increases with the increase in the temperature in case of a liquid?</h3><h2><em>Va</em><em>pour</em><em> </em><em> </em><em>Pressure</em><em> </em></h2>

Explanation:

When a closed container contains liquid, higher the temperature, higher the evaporation the evaporation will be.

So Vapour Pressure should be the correct answer.

6 0
2 years ago
Read 2 more answers
Estimate the molar mass of a gas that effuses at 1.6 times the effusion rate of CO2
Vlada [557]
To estimate the molar mass of the gas, we use Graham's law of effusion. This relates the rates of effusion of gases with their molar mass. We calculate as follows:

r1/r2 = √(m2/m1)    

where r1 would be the effusion rate of the gas and r2 is for CO2, M1 is the molar mass of the gas and M2 would be the molar mass of CO2 (44.01 g/mol) 

r1 = 1.6r2

1.6 = √(44.01 / m1)
m1 = 17.19 g/mol
7 0
3 years ago
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