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3 years ago

A displacement vector with a magnitude of 20. meters could have perpendicular components with magnitudes of

2 answers:

5 0

12 m and 16 m :) The answer is simple, I got it wrong on a test and this was the answer .... sorry can someone help us out??

eduard3 years ago

3 0

<h3><u>Answer;</u></h3>

The perpendicular components <em><u>h</u></em><em><u>ave a magnitude of 12 and 16</u></em>

<h3><u>Explanation;</u></h3>

To find the magnitude of the resultant vector, the formula is written as:

R² = x² + y²,

where

x and y are the perpendicular vectors along x and y axes, respectively.

Therefore, any pair of x and y must satisfy the given equation. There are a lot of possibilities.

Let's say, if x = 12, then,

20² = 12² + y²

y = 16

Thus, One possibility would be a horizontal x vector equal to 12 m, and a vertical y vector equal to 16 m.

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A block of mass m=1.2 kg is held at rest against a spring with a force constant k=730N/m. Initially the spring is compressed a d

igor_vitrenko [27]

Answer:

Explanation:

potential energy of compressed spring

= 1/2 k d²

= 1/2 x 730 d²

= 365 d²

This energy will be given to block of mass of 1.2 kg in the form of kinetic energy .

Kinetic energy after crossing the rough patch

= 1/2 x 1.2 x 2.3²

= 3.174 J

Loss of energy

= 365 d² - 3.174

This loss is due to negative work done by frictional force

work done by friction = friction force x width of patch

= μmg d , μ = coefficient of friction , m is mass of block , d is width of patch

= .44 x 1.2 x 9.8 x .05

= .2587 J

365 d² - 3.174 = .2587

365 d² = 3.4327

d² = 3.4327 / 365

= .0094

d = .097 m

= 9.7 cm

If friction increases , loss of energy increases . so to achieve same kinetic energy , d will have to be increased so that initial energy increases so compensate increased loss .

5 0

3 years ago

A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but had twice as much mass,

fomenos

Answer:

The momentum would be doubled

Explanation:

The magnitude of the momentum of the freight train is given by:

$p=mv$

where

m is the mass of the train

v is its speed

In this problem, we have that the speed of the train is unchanged, while the mass of the train is doubled:

$m'=2m$

therefore, the new momentum is

$p'=m'v=(2m)v=2(mv)=2p$

so, the momentum has also doubled.

7 0

3 years ago

What’s up world or people

Korolek [52]

Hi how are you?

Are you a Libra?

8 0

3 years ago

A bug splats against the windshield of a car traveling at high speeds down a backcountry road. Which statement correctly compare

zvonat [6]

Answer:

C. The bug's change in momentum is equal to the car's change in momentum.

Explanation:

As we know by Newton's 2nd law

$F = \frac{\Delta P}{\Delta t}$

here we have also know that when car hits the bug then force applied by wind shield on the bug is same as the force applied by the bug on the car's wind shield as per Newton's III law

$F_{12} = F_{21}$