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Pavel [41]
3 years ago
10

-poopp poopoop jujuj

Physics
2 answers:
san4es73 [151]3 years ago
3 0

Answer:

okay.........

Explanation:

jarptica [38.1K]3 years ago
3 0

Answer:

thats awesome

Explanation:

PLEASE MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!!!

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What are the Rules of magnetism
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all the allials must be aligned in the same direction

magnets are affected by heat, drops, and improper storage

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3 years ago
A 4.0-m-diameter playground merry-go-round, with a moment of inertia of
HACTEHA [7]

Answer:

7.1 ms⁻¹

Explanation:

d = diameter of merry-go-round = 4 m

r = radius of merry-go-round = \frac{d}{2} =  \frac{4}{2} = 2 m

I = moment of inertia = 500 kgm²

w_{i} = angular velocity of merry-go-round before ryan jumps = 2.0 rad/s

w_{f} = angular velocity of merry-go-round after ryan jumps = 0 rad/s

v = velocity of ryan before jumping onto the merry-go-round

m = mass of ryan = 70 kg

Using conservation of angular momentum

Iw_{i} - m v r = (I + mr^{2})w_{f}

(500)(2.0) - (70) v (2) = (I + mr^{2})(0)

1000 = 140 v

v = 7.1 ms⁻¹

5 0
3 years ago
An electron enters the gap between the plates of a capacitor at the center of the gap traveling parallel to theplates at 2.0 x 1
Svetlanka [38]

Answer:

How far will the electron travel beforehitting a plate is 248.125mm

Explanation:

Applying Gauss' law:

Electric Field E = Charge density/epsilon nought

Where charge density=1.0 x 10^-6C/m2 & epsilon nought= 8.85× 10^-12

Therefore E = 1.0 x 10^-6/8.85× 10^-12

E= 1.13×10^5N/C

Force on electron F=qE

Where q=charge of electron=1.6×10^-19C

Therefore F=1.6×10^-19×1.13×10^5

F=1.808×10^-14N

Acceleration on electron a = Force/Mass

Where Mass of electron = 9.10938356 × 10^-31

Therefore a= 1.808×10^-14 /9.11 × 10-31

a= 1.985×10^16m/s^2

Time spent between plate = Distance/Speed

From the question: Distance=1cm=0.01m and speed = 2×10^6m/s^2

Therefore Time = 0.01/2×10^6

Time =5×10^-9s

How far the electron would travel S =ut+ at^2/2 where u=0

S= 1.985×10^16×(5×10^-9)^2/2

S=24.8125×10^-2m

S=248.125mm

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3 years ago
What can a drop of liquid mercury be described as
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