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polet [3.4K]
3 years ago
14

What question could you ask about kinetic energy which will include the variables that affect it?

Physics
2 answers:
Gemiola [76]3 years ago
4 0

Answer:

  • <u>Kinetic Energy (K.E):</u>

The K.E is acquired or possessed by the body due to its virtue of motion. As the K.E is based upon the mass of the body, m which remains the same for each object, while the K.E also depends upon the square of velocity,v of the same body(while it is in motion), which is a variable.

  • K.E=1/2 m×v².

Explanation:

  • <u>K.E and velocity,v:</u>

The K.E acquired by the body depends upon the constant value of mass,m and the variable component of velocity,v. As the velocity of the body changes along time change,Δt.

Juli2301 [7.4K]3 years ago
3 0
KE= (1/2) mv²

So, the variables we need to include in our question would be a varable for a mass(m) of an object at some velocity(v).

My Answer:

(This is just an example question, yours can be different)
What is the Kinetic Energy experienced by an bouncy ball rolling at 7m/s (that's your velocity) across a frictionless surface that has a mass(m) of 10 grams? 


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amid [387]

Answer:

v_{f} = 74 m/s, F = 230 N

Explanation:

We can work on this exercise using the relationship between momentum and moment

        I = ∫ F dt = Δp

bold indicates vectors

we can write this equations in its components

X axis

       Fₓ t = m ( -v_{xo})

Y axis  

        t = m (v_{yf} - v_{yo})

in this case with the ball it travels horizontally v_{yo} = 0

Let's use trigonometry to write the final velocities and the force

        sin 30 = v_{yf} / vf

        cos 30 = v_{xf} / vf

        v_{yf} = vf sin 30

        v_{xf} = vf cos 30

         sin40 = F_{y} / F

         F_{y} = F sin 40

         cos 40 = Fₓ / F

         Fₓ = F cos 40

let's substitute

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we have two equations and two unknowns, so the system can be solved

        F cos 40 0.1 = 0.4 (v_{f} cos 30 - 20)

        F sin 40 0.1 = 0.4 v_{f} sin 30

we clear fen the second equation and subtitles in the first

         F = 4 sin30 /sin40     v_{f}

         F = 3.111 v_{f}

        (3,111 v_{f}) cos 40 = 4 v_{f} cos 30 - 80

        v_{f} (3,111 cos 40 -4 cos30) = - 80

        v_{f} (- 1.0812) = - 80

        v_{f} = 73.99

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          F = 3.111 73.99

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6 0
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Explanation:

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Answer:

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Explanation:

your welcome

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2. None of these occur

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