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polet [3.4K]
3 years ago
14

What question could you ask about kinetic energy which will include the variables that affect it?

Physics
2 answers:
Gemiola [76]3 years ago
4 0

Answer:

  • <u>Kinetic Energy (K.E):</u>

The K.E is acquired or possessed by the body due to its virtue of motion. As the K.E is based upon the mass of the body, m which remains the same for each object, while the K.E also depends upon the square of velocity,v of the same body(while it is in motion), which is a variable.

  • K.E=1/2 m×v².

Explanation:

  • <u>K.E and velocity,v:</u>

The K.E acquired by the body depends upon the constant value of mass,m and the variable component of velocity,v. As the velocity of the body changes along time change,Δt.

Juli2301 [7.4K]3 years ago
3 0
KE= (1/2) mv²

So, the variables we need to include in our question would be a varable for a mass(m) of an object at some velocity(v).

My Answer:

(This is just an example question, yours can be different)
What is the Kinetic Energy experienced by an bouncy ball rolling at 7m/s (that's your velocity) across a frictionless surface that has a mass(m) of 10 grams? 


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You have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 690.0 kg and was tra
kirza4 [7]

Answer:

115 km/h

Explanation:

m_1 = Mass of car A = 690 kg

m_2 = Mass of car B = 520 kg

g = Acceleration due to gravity = 9.81 m/s²

a = Acceleration

u = Initial velocity

v = Final velocity

a=\mu g\\\Rightarrow a=0.75\times 9.81\\\Rightarrow a=7.3575\ m/s^2

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 7.3575\times 6+0^2}\\\Rightarrow v=9.396\ m/s

m_1u_1 + m_2u_2 =(m_1 + m_2)v\\\Rightarrow u_1=\frac{(m_1 + m_2)v-m_2u_2}{m_1}\\\Rightarrow u_1=\frac{(690+520)9.396-520\times -\frac{74}{3.6}}{690}\\\Rightarrow u_1=31.96\ m/s

Converting to km/h

31.96\times 3.6=115.056\ km/h

Initial velocity of car A = 115 km/h

7 0
3 years ago
Calculate the force of gravity on the 0.60-kg mass if it were 1.3×107m above Earth's surface (that is, if it were three Earth ra
Vladimir79 [104]
The force of gravity between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is their separation

In this problem, the mass of the object is m_1=0.60 kg, while the Earth's mass is m_2=5.97 \cdot 10^{24} kg. Their separation is r=1.3 \cdot 10^7 m, therefore the gravitational force exerted on the object is
F=(6.67 \cdot 10^{-11}m^3 kg^{-1} s^{-2}) \frac{(0.60 kg)(5.97 \cdot 10^{24} kg)}{(1.3 \cdot 10^7 m)^2}=1.4 N
5 0
3 years ago
If the ac peak voltage across a 100-ohm resistor is 120 V, then the average power dissipated by the resistor is ________
Kazeer [188]

Answer:

The average power dissipated is 72 W.

Explanation:

Given;

peak voltage of the AC circuit, V₀ = 120 V

resistance of the resistor, R = 100 -ohm

The average power dissipated by the resistor is given by;

P_{avg} = \frac{1}{2} I_oV_o= I_{rms}V_{rms} = \frac{V_{rms}^2}{R}

where;

V_{rms} is the root-mean-square-voltage

V_{rms} = \frac{V_o}{\sqrt{2}} \\\\V_{rms} = \frac{120}{\sqrt{2}}\\\\V_{rms} = 84.853 \ V

The average power dissipated by the resistor is calculated as;

P_{avg} = \frac{V_{rms}^2}{R}\\\\P_{avg} = \frac{84.853^2}{100}\\\\P_{avg} = 72 \ W

Therefore, the average power dissipated is 72 W.

5 0
3 years ago
Which instrument, a cello or a violin, produces a higher-pitched sound? Explain your answer.
anastassius [24]
I'm pretty sure a violin produces a higher-pitched sound. I play the violin and it's pretty loud. (Hope this helps)
4 0
3 years ago
Read 2 more answers
An ideal gas, initially at a pressure of 11.2 atm and a temperature of 299 K, is allowed to expand adiabatically until its volum
Tju [1.3M]

Answer:

The pressure is  P_2  =  4.25 \ a.t.m

Explanation:

From the question we are told that

   The initial pressure is P_1  =  11.2\ a.t.m

   The  temperature is  T_1 =   299 \ K

   

Let the first volume be  V_1 Then the final volume will be  2 V_1

 Generally for a diatomic  gas

           P_1 V_1 ^r  =  P_2  V_2  ^r

Here r is the radius of the molecules which is  mathematically represented as

    r =  \frac{C_p}{C_v}

Where C_p \  and\   C_v are the molar specific heat of a gas at constant pressure and  the molar specific heat of a gas at constant volume with values

     C_p=7 \  and\   C_v=5

=>   r =  \frac{7}{5}

=>  11.2*( V_1 ^{\frac{7}{5} } ) =  P_2  *  (2 V_1 ^{\frac{7}{5} } )

=>   P_2  =  [\frac{1}{2} ]^{\frac{7}{5} } * 11.2

=>  P_2  =  4.25 \ a.t.m

8 0
3 years ago
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