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Liono4ka [1.6K]
2 years ago
9

Propane camping stoves produce heat by the combustion of gaseous propane (C3H8). Balance the skeletal equation for the combustio

n of propane.
C3H8(g)+O2(g)→CO2(g)+H2O(g)
Chemistry
2 answers:
Darina [25.2K]2 years ago
3 0
Easy (: 

C₃H₈ (g) + O₂ (g) ---> CO₂ (g) + H₂O 

1 C₃H₈ (g) +  5 O₂ (g) ---> 3 CO₂ (g) + 4 H₂O 

With this there is the same amount of elements on each side (You take the larger number in front and multiply it by whats after it. So you have 3 C, 8 H, and 10 O on one side, and then the next mirrors is with 3 C, 8 H, and 10 O. 

vodomira [7]2 years ago
3 0

Explanation:

The given reaction is as follows.

           C_{3}H_{8}(g) + O_{2} \rightarrow CO_{2}(g) + H_{2}O(g)

A balanced reaction is defined as the reaction which contains equal number of atoms on both reactant and product side.

Number of atoms on reactant side are as follows.

C = 13

H = 8

O = 2

Number of atoms on product side are as follows.

C = 1

O = 3

H = 2

Therefore, to balance this equation we multiply oxygen by 5 on reactant side. Also, we multiply CO_{2} by 3 and H_{2}O by 4 on product side by 2. Hence, the complete balanced chemical equation will be as follows.

     C_{3}H_{8}(g) + 5O_{2} \rightarrow 3CO_{2}(g) + 4H_{2}O(g)

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Suppose you carry out a titration involving 1.90 molar CsOH and an unknown concentration of HI. To bring the reaction to its end
Mariulka [41]

The concentration of the HI solution is 0.75M.

<h3>How do we calculate the required concentration?</h3>

Required concentration of any solution used in titration will be calculated by using the below equation as:

M₁V₁ = M₂V₂, where

M₁ & V₁ are the molarity and volume of CsOH.

M₂ & V₂ are the molarity and volume of HI.

On putting all values from the question, we get

M₂ = (1.9)(9.9) / (25) = 0.75M

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1 year ago
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3 years ago
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If you add 14.22ml of 2.97m hcl (42.2mmol) to an antacid, then neutralize the excess acid with 5.00ml of 0.1055 m naoh (0.528mmo
Vinvika [58]

Given data:

Volume of HCl = 14.22 ml

Molarity of HCl = 2.97 M

mmoles of HCl = 14.22 * 2.97 = 42.2 mmoles

Volume of NaOH = 5.00 ml

Molarity of NaOH = 0.1055 M

mmoles of NaOH = 5.00 *.1055 = 0.5275 mmoles

Since HCl and NaOH combine in a 1:1 ratio

# moles of NaOH = # moles of excess HCl that is neutralized = 0.5275 moles

Now, the total moles of HCl taken = # mmoles HCl neutralized by antacid + # mmoles of excess HCl

42.2 = mmoles HCl neutralized by antacid + 0.5275

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mmoles of HCl neutralized by antacid = 42.2 - 0.5275 = 41.6725 mmoles = 41.7 mmoles


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2 years ago
How many calories of heat are required to raise the temperature of 1.00kg of water from 10.2 degrees Celsius to 26.8 degrees Cel
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Answer:

Explanation:

we know that specific heat is the amount of heat required to raise the  temperature of substance by one degree mathmeticaly

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C for water is 4.184

therefore

Q=1.00*4.184*16.6

Q=69.4 j

now we have to covert joule into calorie

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x calorie=69.4 j/2

so 69.4 j =34.7 calorie thats why 34.7 calorie heat is required to raise the temperature of water from 10.2 to 26.8 degree celsius

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