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Shkiper50 [21]
3 years ago
12

Calculate the solubility of argon in water at an atmospheric pressure of 0.370 atm (a typical value at high altitude).

Chemistry
1 answer:
lidiya [134]3 years ago
5 0

Answer:

4.84 × 10⁻⁶ M

Explanation:

First, we will calculate the partial pressure of Ar (pAr) using the following expression.

pAr = P × χAr

where,

P: total pressure

χAr: mole fraction

pAr = P × χAr

pAr = 0.370 atm × 9.34 × 10⁻³

pAr = 3.46 × 10⁻³ atm

We can find the solubility of Ar in water (S) using Henry's law.

S = kH × pAr

where

kH: Henry's constant

S = kH × pAr

S = 1.40 × 10⁻³ M/atm  × 3.46 × 10⁻³ atm

S = 4.84 × 10⁻⁶ M

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Explanation:

because it is an allotrope of carbon

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If 30 ml of water containing 15 mg of salicylate is extracted with 30 ml of chloroform, 2.59 mg of salicylate remains in the wat
In-s [12.5K]

Answer:

Distribution coefficient: 4.79

Explanation:

Distribution coefficient is the ratio between equilibrium concentration of non-aqueous phase and aqueous phase where both solvents are inmiscible. The equation for the problem is:

Distribution coefficient: Concentration in chloroform / Concentration in Water

<em>Concentration in water: 2.59mg / 30mL = 0.08633mg/mL</em>

<em>Concentration in chloroform: (15mg-2.59mg) / 30mL = 0.4137mg/mL</em>

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Distribution coefficient: 0.4137mg/mL / 0.08633mg/mL

<h3>Distribution coefficient: 4.79</h3>
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3 years ago
Chemistry! Help! Please!! Thanks
Vladimir79 [104]

Answers:

1. 3-ethyl-3-methylheptane; 2. 2,2,3,3-tetramethylpentane; 3. hexa-2,4-diene.

Explanation:

<em>Structure 1 </em>

  1. Identify and name the longest continuous chain of carbon atoms (the main chain has 7 C; ∴ base name = heptane).
  2. Identify and name all the substituents [a 1C substituent (methyl) and a 2C substituent (methyl).
  3. Number the main chain from the end closest to a substituent.
  4. Identify the substituents by the number of the C atom on the main chain. Use hyphens between letters and numbers (3-methyl, 3-ethyl).
  5. Put the names of the substituents in alphabetical order in front of the base name with no spaces (3-ethyl-3-methylheptane)

<em>Structure 2</em>

  1. 5C. Base name = pentane
  2. Four methyl groups.
  3. Number from the left-hand end.
  4. If there is more than one substituent of the same type, identify each substituent by its locating number and use a multiplying prefix to show the number of each substituent. Use commas between numbers (2,2,3,3-tetramethyl).
  5. The name is 2,2,3,3-tetramethylpentane.

<em>Structure 3 </em>

  1. Identify and name the longest continuous chain of carbon atoms that passes through as many double bonds as possible. Drop the <em>-ne</em> ending of the alkane to get the root name <em>hexa-</em>.
  2. (No substituents).
  3. Number the main chain from the end closest to a double bond.
  4. If there is more than one double bond use a multiplying prefix to indicate the number of double bonds (two double bonds = diene) and use the smaller of the two numbers of the C=C atoms as the double bond locators (2,4-diene)
  5. Put the functional group name at the end of the root name (hexa-2,4-diene).

<em>Note</em>: The name 2,4-hexadiene is <em>acceptable</em>, but the <em>Preferred IUPAC Name</em> puts the locating numbers as close as possible in front of the groups they locate.

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The number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.

<h3>How to calculate number of moles?</h3>

The number of moles of a substance can be calculated by dividing the mass of the substance by its molar mass. That is;

no. of moles = mass ÷ molar mass

According to this question, a chemist will use a sample of 30 g of ethanol (CH3CH2OH) in an experiment. The number of moles can be calculated as follows:

Molar mass of ethanol = 12(2) + 1(5) + 17 = 46g/mol

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Therefore, the number of moles of ethanol the chemist will use in the experiment involving 30g of ethanol is 0.65moles.

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