Calculate the solubility of argon in water at an atmospheric pressure of 0.370 atm (a typical value at high altitude).
1 answer:
Answer:
4.84 × 10⁻⁶ M
Explanation:
First, we will calculate the partial pressure of Ar (pAr) using the following expression.
pAr = P × χAr
where,
P: total pressure
χAr: mole fraction
pAr = P × χAr
pAr = 0.370 atm × 9.34 × 10⁻³
pAr = 3.46 × 10⁻³ atm
We can find the solubility of Ar in water (S) using Henry's law .
S = kH × pAr
where
kH: Henry's constant
S = kH × pAr
S = 1.40 × 10⁻³ M/atm × 3.46 × 10⁻³ atm
S = 4.84 × 10⁻⁶ M
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