increased with an increased current flow
Explanation:
it dosent depend on the weights of the items. I'll reach the ground at same time taking as no air friction or restrictions.
i.e
v = u + gt
whte v is final velocity of the object
u is initial velocity of the object
g is acceleration due to gravity and
t is time. thanks
please if found helpful rate brainliest
Answer:
Because there is not as much cold as it was in France.
Explanation:
The average temperature in France during January ranges from 2.7° to 7.2° celsius which makes it the coldest month of the year. But since she comes to know that average temperature in Annville ranges 31° celsius which implies that the temperature is normal there and therefore, she packs sleeveless tops and shorts. Coats would not be required in a hot weather and hence, she does not pack it.
Answer:
130 km at 35.38 degrees north of east
Explanation:
Suppose the HQ is at the origin (x = 0, y = 0)
So the coordinates of the helicopter after the 1st flight is
![x_1 = -120cos70^o = -41.04 km](https://tex.z-dn.net/?f=x_1%20%3D%20-120cos70%5Eo%20%3D%20-41.04%20km)
![y_1 = -120sin70^o = -112.763 km](https://tex.z-dn.net/?f=y_1%20%3D%20-120sin70%5Eo%20%3D%20-112.763%20km)
After the 2nd flight its coordinate would be:
![x_2 = x_1 - 75sin60^o = -41.04 - 64.95 = -106km](https://tex.z-dn.net/?f=x_2%20%3D%20x_1%20-%2075sin60%5Eo%20%3D%20-41.04%20-%2064.95%20%3D%20-106km)
![y_2 = y_1 + 75cos60^o = -112.763 + 37.5 = -75.263 km](https://tex.z-dn.net/?f=y_2%20%3D%20y_1%20%2B%2075cos60%5Eo%20%3D%20-112.763%20%2B%2037.5%20%3D%20-75.263%20km)
So in order to fly back to its HQ it must fly a distance and direction of
north of east
Answer:
We conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.
Hence, option D is correct.
Explanation:
Given
To determine
Mass m = ?
Important Tip:
-
The mass of a rock can be found using the formula F = ma
Using the formula
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
where
- a is the acceleration (m/s²)
now substituting F = 500, and a = 75 m/s² in the formula
![F = ma](https://tex.z-dn.net/?f=F%20%3D%20ma)
![500 = m(75)](https://tex.z-dn.net/?f=500%20%3D%20m%2875%29)
switch sides
![m\left(75\right)=500](https://tex.z-dn.net/?f=m%5Cleft%2875%5Cright%29%3D500)
Divide both sides by 75
![\frac{m\cdot \:75}{75}=\frac{500}{75}](https://tex.z-dn.net/?f=%5Cfrac%7Bm%5Ccdot%20%5C%3A75%7D%7B75%7D%3D%5Cfrac%7B500%7D%7B75%7D)
simplify
![m=\frac{20}{3}](https://tex.z-dn.net/?f=m%3D%5Cfrac%7B20%7D%7B3%7D)
kg
Therefore, we conclude that the mass of a rock with a force of 500 N and an acceleration of 75 m/s² is 6.7 kg.
Hence, option D is correct.