Answer:
Compound A: Benzoyl chloride
Compound B: Benzaldehyde - (tBuO)₃Al complex
Compound C: Benzaldehyde
Compound D: Benzyl alcohol
Explanation:
The lithium tri-tert-butoxyaluminum hydride that the first student used is a milder reagent than LAH and will stop reacting at the aldehyde.
The LAH that the second student used is much more reactive and will continue to reduce the benzoic acid as far as possible, going all the way to the alcohol.
See the attachment for the reaction steps.
Answer:
kinds of fish
Explanation:
I saw at the picture many kinds of fish but they are all in the sea or fish pond maybe.
Answer:
a. 0.27 = Kc
b. 8.19×10⁻⁵ = Kp
Explanation:
The reaction is this: 3H₂(g) + N₂ (g) ⇄ 2NH₃ (g)
As we have the moles of each in the equilibrium and the volume is 1L, we assume the concentrations as molarity.
1.6981 mol/L → H₂
0.5660 mol/L → N₂
0.8679 mol/L → NH₃
Let's make the expression for Kc
Kc = [NH₃]² / [N₂] . [H₂]³
Kc = 0.8679² / 0.5660 . 1.6981³
Kc = 0.27
Let's calculate Kp, derivated from Kc
Kp = Kc . (RT)^Δn where:
Δn is the difference between final moles - initial moles. It is governed by stoichiometry. For this case 2 - (1+3) = -2
Δn it is always for gases
R is the Ideal gases constant
T is Absolute T°
Let's replace data → 0.27 . (0.082 . 700K)⁻² = Kp
8.19×10⁻⁵ = Kp
Answer: A
Explanation: i took the test
Answer:
new volume is 1215mL
Explanation:
using Charles law , the volume of a fixed mass of gas is directly proportional to its temperature provide that pressure is kept constant.
V1=900mL ,
convert the temperatures from Celsius to kelvin temperature.
T1 =27°C =27+273 =300K
T2 =132°C = 132+273=405K
V2= 1215mL
