Solubility of a compound in water can be referred to as the amount of the compound that can be dissolved in 1 L of the solvent (water) at any given temperature. Solubility of a compound can be expressed in the units of g/L or mg/L.
Given that the solubility of calcium carbonate in water = 14 mg/L
We have to calculate the volume of water that can dissolve 11 g of calcium carbonate.
Converting 11 g calcium carbonate to mg:

Volume of water that would dissolve 11000 mg calcium carbonate
= 
=785.7 L
Rounding the volume 785.7 L to two significant figures, we get 790 L water.
Therefore, we would need 790 L water to completely dissolve 11 g of calcium carbonate.
Answer:
it depends on the assignment but im down
Explanation:
The answer is B) dry and irregular
First, make sure all three measurements have the same unit (I recommend meters because that's what the question calls for)
1.0m=1.0m
5.6cm=0.056m
2.1mm=0.0021m
Then, you just want to multiply the three together to get the total volume.
1.0X0.056X0.0021=0.0001176 or 0.00012, if your teacher wants you to use proper sig figs