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SCORPION-xisa [38]
3 years ago
14

The percent composition of all elements in HClO3 is:

Chemistry
1 answer:
ser-zykov [4K]3 years ago
6 0
The answer is <span>b. 1% H, 42% Cl, 57% O.</span>

Let's first calculate a molar mass (M) of HClO₃. <span>Molar mass is a mass of 1 mole of a substance. It can be expressed as the sum of relative atomic masses (Ar), which are masses of atoms of the elements:
</span>M(HClO₃) = Ar(H) + Ar(Cl) + 3Ar(O)

Ar(H) = 1 u 
Ar(Cl) = 35.5 u
Ar(O) = 16 u
M(HClO₃) = Ar(H) + Ar(Cl) + 3Ar(O) = 1 + 35.5 + 3 · <span>16 = 84.5 u

Now, we just need to calculate mass percent of each element using the proportion:
Ar : x = M : 100%                   </span>⇒      x = Ar ÷ M · 100%

Hydrogen: x = Ar(H) ÷ M · 100% = 1 ÷ 84.5 · 100% = 1.2% ≈ 1%
Chlorine: x = Ar(Cl) ÷ M · 100% = 35.5 ÷ 84.5 <span>· 100% = 42%
</span>Oxygen: x = 3Ar(O) ÷ M · 100% = 48 ÷ 84.5 · 100% = 56.8% ≈ 57%

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