Answer:
8 cm3
Explanation:
The volume of this irregular solid will calculated as the difference between the final volume and the initial volume;
The final volume of the water and the solid is 25 ml
The initial volume of the water alone was 17 ml
The volume of the irregular solid is thus approximately;
25 - 17 = 8 ml
We then use the conversion;
1 cm3 = 1 mL
Thus the volume of the solid is 8 cm3
Answer:
See explaination
Explanation:
See attachment for the drawing of the intermediate products b and c (both are neutral; omit byproducts).
Answer:
b)4.46 L/hr
Explanation:
To solve this question we need to convert the mL to liters (Using the conversion of 1000mL = 1L) and convert the time from seconds to hours (3600s = 1hr)
<em>mL to L:</em>
1.24mL/s * (1L / 1000mL) = 0.00124L/s
<em>seconds to hours:</em>
0.00124L/s * (3600s / 1hr) = 4.46L/hr
Right answer is:
<h3>b)4.46 L/hr
</h3>
Answer:
When [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate
Explanation:
Ksp of BaF₂ is:
BaF₂(s) ⇄ Ba²⁺(aq) + 2F⁻(aq)
Ksp = 1.7x10⁻⁶ = [Ba²⁺] [F⁻]²
The solution will produce BaF₂(s) -precipitate- just when [Ba²⁺] [F⁻]² > 1.7x10⁻⁶.
As the concentration of [Ba²⁺] is 0.0144M, the product [Ba²⁺] [F⁻]² will be equal to ksp just when:
1.7x10⁻⁶ = [Ba²⁺] [F⁻]²
1.7x10⁻⁶ = [0.0144M] [F⁻]²
1.18x10⁻⁴ = [F⁻]²
0.0109M = [F⁻]
That means, when [F⁻] exceeds 0.0109M concentration, BaF₂ will precipitate
Mole number of 75 g is 0.4 mol. NO2 is 0.8 mol and is 36.8 g.
