Question

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Answer 1

The answer is A.

Let's make the problem simpler by naming
${(1.14)}^{x} = t$
Then,
$f(x) = 600t \\ g(x) = 450t$
Since we're trying to find the total Bisons in both regions, it is the sum of the two functions:
$h(x) = f(x) + g(x)$
Substituting in their values,
$h(x) = (600t) + (450t) = 1050t$
Finally, let's make sure to plug in the true value of t again:
$h(x) = 1050t = 1050 {(1.14)}^{x}$
Thus, A is the correct answer.

Answer 2

h(x) = f(x) + g(x)

  = 600 (1.14)^x + 450(1.14)^x

1050 1.14^x

Choice A