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aivan3 [116]
2 years ago
14

How many ethyne molecules are contained in 84.3 grams of ethyne (C2H2)?

Chemistry
2 answers:
ololo11 [35]2 years ago
6 0
(~26grams/mole) and Avogadros # (6.022x10^23) 84.3grams x 1mole/26grams x 6.022x10^23 molecules/mole = 1.95x10^24 molecules of C2H2
ahrayia [7]2 years ago
6 0

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms or molecules present in 1 mole.

As, it is given that mass of ethyne is 84.3 g. Hence, calculate its number of moles as follows.

          No. of moles = \frac{mass}{\text{molar mass}}

                                 = \frac{84.3 g}{26.04 g/mol}

                                 = 3.24 mol

Therefore, calculate number of ethyne molecules as follows.

                 3.24 mol \times 6.022 \times 10^{23} atoms

                    = 19.51 \times 10^{23} atoms

Thus, we can conclude that there are 19.51 \times 10^{23} atoms in 84.3 grams of ethyne.

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