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Yuliya22 [10]
3 years ago
10

Which shows the expression below simplified? 0.00048 ÷ (6 × 10-4)

Mathematics
1 answer:
tatyana61 [14]3 years ago
5 0

0.00048 ÷ (6 × 10-4)  should be rewritten as 0.00048 ÷ (6 × 10^(-4) ).  The symbol " ^ " denotes exponentiation.  Without parentheses here, it appears that you want to subtract 4 from 10, which is inappropriate.

First focus on the " (6 × 10^(-4) )"  This is equivalent to  6 / (10^4).  To divide 0.00048 by 6 / (10^4), invert the divisor and then multiply:

0.00048 * (10^4 / 6) = 0.00008*10^4, or  8*10^(-5)*10^(4) = 8*10^(-1) = 8/10 = 0.8.

Note that all of the possible answer choices need to be re-written.  10-1, for example, must be re-written as 10^(-1).

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7 0
3 years ago
Let the random variable X be the number of rooms in a randomly chosen owner-occupied housing unit in a certain city. The distrib
natali 33 [55]

Answer:

a) X is a discrete random variable.

b) 2% probability of choosing a unit with 10 rooms

c) 98% probability that a unit chosen at random is not a 10-room unit

d) 30% probability that a unit chosen at random has less than five rooms

e) 7% probability that a unit chosen at random has less than five rooms

Step-by-step explanation:

The distribution means that:

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms.

23% probability that a randomly chosen owner-occupied housing unit in a certain city has 4 rooms.

36% probability that a randomly chosen owner-occupied housing unit in a certain city has 5 rooms.

19% probability that a randomly chosen owner-occupied housing unit in a certain city has 6 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 7 rooms.

5% probability that a randomly chosen owner-occupied housing unit in a certain city has 8 rooms.

3% probability that a randomly chosen owner-occupied housing unit in a certain city has 9 rooms.

?% probability that a randomly chosen owner-occupied housing unit in a certain city has 10 rooms.

(a) Is X a discrete or continuous random variable?

X is the number of rooms in a randomly selected house. The number of rooms is a countable variable, that is, only assumes values like 1,2,3,4,... You cannot have 3.5 rooms, for example.

So X is a discrete random variable.

(b) What must be the probability of choosing a unit with 10 rooms?

The sum of all probabilities must be 100%(1 decimal). So

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 + ? = 1

0.98 + ? = 1

? = 0.02

2% probability of choosing a unit with 10 rooms

(c) What is the probability that a unit chosen at random is not a 10-room unit?

0.07 + 0.23 + 0.36 + 0.19 + 0.05 + 0.05 + 0.03 = 0.98

98% probability that a unit chosen at random is not a 10-room unit

(d) What is the probability that a unit chosen at random has less than five rooms?

7% probability it has 3 rooms

23% probability it has 4 rooms. So

7+23 = 30% probability that a unit chosen at random has less than five rooms

(e) What is the probability that a unit chosen at random has three rooms?

7% probability that a randomly chosen owner-occupied housing unit in a certain city has 3 rooms. So

7% probability that a unit chosen at random has less than five rooms

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3 years ago
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