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neonofarm [45]
3 years ago
8

Assuming the final solution will be diluted to 1.00 l , how much more hcl should you add to achieve the desired ph?

Chemistry
1 answer:
solong [7]3 years ago
4 0
H = 2.7, therefore amount of H+ needed is 10^-2.7 M 

<span>u haf 80 ml of hcl and 90 ml of naoh left, therefore 20 ml of hcl used, and 10ml of naoh used. </span>

<span>mols of H+ = 0.02 x 7 x 10^-2 = 1.4 x 10^-3 </span>
<span>mols of OH- = 0.01 x 5 x 10^-2 = 5 x 10^-4 </span>

<span>H+ and OH- neutralise each other, so remaining mols of H+ = 9 x 10^-4 </span>

<span>u need 10^-2.7 mols of H+, so 10^-2.7 - 9 x 10^-4 = 0.001095 mol </span>

<span>vol of HCL needed = 0.001095 / 7 x 10^-2 = 0.0156 L = 15.6 mL</span>
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What is the mass of 2.40 moles of magnesium chloride, mgcl2
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Hey there!

MgCl₂

Find molar mass of magnesium chloride.

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--------------------  

          95.211 grams

One mole of magnesium chloride has a mass of 95.211 grams.

We have 2.40 moles.

2.40 x 95.211 = 228.5

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The mass of 2.40 moles of magnesium chloride is 229 grams.

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The gravitational force exerted by an object is given by F = mg, where F is the force in newtons, m is the mass in kilograms, an
Andre45 [30]

The height of the column is 0.457 m and the mass of the atmosphere is calculated as 1.03 × 10 ⁴ kg.

<h3>What is Pascal? </h3>

Pascal is defined as the force per unit area. It expressed in Newton pr square meter of area.

1 Pa = 1 N / m²

Pressure = force / Area

According to the question, the expression of force is as given below

F = mg

where,

F is the force,

m is the mass,

g is equal to the acceleration due to the gravity

Now, the area of the atmosphere is 1 m².The pressure is 1 atm. Pressure in Pascal.

1 atm = 1.01325 × 10 5pa

Therefore, the expression for pascal become as follows.

1.01325 × 10 5 pa = mg /area

1.01325 × 10 5 pa = m × 9.81 m/s² / 1 m²

M = 1.01325 × 10 5 pa × 1 m² / 9.81 m² × 1 Nm -² /1 pa × 1 kg m-² / 1 N

1.03 × 10 ⁴ kg

Given,

The density is 22.6 g /mL , pressure is 1 atm, and area is 1 m²

The relation between density and pressure can be given as follows.

P = hpg… … …(1 )

were , h is the height of the column

p is the density.

Hpg = 1.01325 × 10 5 pa × 1 N/m² /1 pa

H = 1.01325 × 10 5 N/m² / pg × 1 kg ms-² / 1 N

= 1.01325 × 10 5 kg m-¹ s -² / 22.6 g mL -1 × 1 kg/ 10 ³ g × 1 mL / 10 -6 m ³ × 9.81 m s- ²

= 0.457 m

Therefore, the height of the column is 0.457 m.

Thus, we concluded that the height of the column is 0.457 m and the mass of the atmosphere is calculated as 1.03 × 10 ⁴ kg.

learn more about density:

brainly.com/question/952755

#SPJ4

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2 years ago
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