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Papessa [141]
3 years ago
9

An industrial chemist studying bleaching and sterilizing prepares several hypochlorite buffers. Find the pH of the following buf

fers.
(
a. 0.090 M HClO and 0.090 M NaClO (
b. 0.090 M HClO and 0.135 M NaClO (
c. 0.135 M HClO and 0.090 M NaClO (
d. One liter of the solution in part (
a. after 0.0050 mol NaOH has been added.
I only need help with (
d. I got 8.07, but that was incorrect
Chemistry
1 answer:
8_murik_8 [283]3 years ago
8 0
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

<span> I got (a). The answer was 7.53. But when I try to solve (d), I keep getting the wrong answer. I subtracted the moles of NaOH from the acid and added the moles to the base. Then I did Ka = (x*([NaClO]+x))/([HClO - x) and then I found the pH</span>

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A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i
IRINA_888 [86]

Answer : The pressure after the temperature change is, 0.752 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T

or,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

where,

P_1 = initial pressure = 0.82 atm

P_2 = final pressure = ?

T_1 = initial temperature = 21^oC=273+21=294K

T_2 = final temperature = -3.5^oC=273+(-3.5)=269.5K

Now put all the given values in the above equation, we get:

\frac{0.82atm}{294K}=\frac{P_2}{269.5K}

P_2=0.752atm

Thus, the pressure after the temperature change is, 0.752 atm

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Which of the following represents the electron configuration of rhodium
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Explanation:

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Lead(II) oxide from an ore can be reduced to elemental lead by heating in a furnace with carbon. Calculate the expected yield of
Lelu [443]

Answer:

53kg is the expected yield of lead

Explanation:

Firstly, in order to solve this question, we need to write the equation of reaction correctly. This is as follows:

PbO(s) + C(s) ---> Pb(l) + CO(g)

We proceed from here. We should get the limiting reactant but this can only be obtained by getting the number of moles of each reactant present.

The formula to use across all boards is that the number of moles is the mass of each of the reactant divided by the molar mass of each of the reactant.

For PBO, mass is 57kg = 57000g

Molar mass of PBO = 223.20g/mol

The number of moles is thus 57,000/223.2 = 255.37 moles

For carbon, mass is also 57kg = 57000g

Molar mass is 12g/mol

Number of moles of carbon = 57000/12 = 4750 moles

From the number of moles, we can see that the number of moles of Carbon is greater than that of PbO. This means that PbO is the limiting reagent.

Hence we use it to calculate percentage yield.

The number of moles of lead formed is the same of number of moles of lead oxide = 255.37 since we have mole ratio of 1 to 1

The molar mass of lead is 207.20g/mol

The mass of lead formed is = moles of lead formed * molar mass of lead = 207.20 * 255.37 = 52,912g which is approximately 53kg

Hence the expected yield is 53kg

6 0
3 years ago
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