Answer:
1,081.1 units of heparin should be given to 298 lb person.
Explanation:
We are given:
Weight of the person = 298 lb = 135.143 kg
Conversion factor used:
1 lb = 0.4535 kg
Number of unit of heparin to be given in an hour = 8.0 units/kg
Number of units given to the patient weighing 135.143 kg :

1,081.1 units of heparin should be given to 298 lb person.
Answer:
He traveled at a speed of 4 m/s with a velocity of 4m/s north, and his acceleration changed when stopping for lunch.
Explanation:
Trust me took test got it right!
The question is incomplete, complete question is :
In an organic structure, you can classify each of the carbons as follows: Primary carbon (1°) = carbon bonded to just 1 other carbon group Secondary carbon (2°) = carbon bonded to 2 other carbon groups Tertiary carbon (3°) = carbon bonded to 3 other carbon groups Quaternary carbon (4°) = carbon bonded to 4 other carbon groups How many carbons of each classification are in the structure below? How many total carbons are in the structure? How many primary carbons are in the structure? How many secondary carbons are in the structure? How many tertiary carbons are in the structure? How many quaternary carbons are in the structure?
Structure is given in an image?
Answer:
There are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.
Explanation:
Total numbers of carbon = 10
Number of primary carbons that is carbon joined to just single carbon atom = 6
Number of secondary carbons that is carbon joined to two carbon atoms = 1
Number of tertiary carbons that is carbon joined to three carbon atoms = 2
Number of quartenary carbons that is carbon joined to four carbon atoms = 1
So, there are 10 carbon atoms in the given structures out of which 6 are 1° , 1 is 2° , 2 are 3° and 1 is 4°.