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solniwko [45]
3 years ago
7

Name 3 muscles of the leg​

Physics
1 answer:
xxTIMURxx [149]3 years ago
4 0

Answer:

calf

Explanation:

jdjdjddjdjdhdhdj

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Law Incorporation [45]

Answer:

no one knows

Explanation:

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Please Help me with any of these possible.
Fiesta28 [93]

alll factor is possible

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A body with a mass of 5 Kg has the same kinetic energy as a second body. The second body has a mass of 10 kg and is moving at a
vitfil [10]
First body:

E_{k_1}=\frac{1}{2}.m.v^2\\
\\
E_{k_1}=\frac{1}{2}.5.v_1^2=\frac{5}{2}.v_1^2

Second body:

E_{k_2}=\frac{1}{2}.m.v_2^2\\
\\
E_{k_2}=\frac{1}{2}.10.(20)^2=2.000 \ J

From description of the task we have:

E_{k_1}=E_{k_2}\\
\\
\frac{5}{2}.v_1^2=2.000 \ J\\
\\
5.v_1^2=4.000 \ J\\
\\
v_{1}^2=800 \ J\\
\\
v_{1}= \sqrt{800} \ J \approx 28,3 \ m/s
7 0
3 years ago
3 characteristics of physical change
Nady [450]

Answer:

Explanation:

A physical property is a characteristic of matter that is not associated with a change in its chemical composition. Familiar examples of physical properties include density, color, hardness, melting and boiling points, and electrical conductivity.

5 0
3 years ago
Read 2 more answers
A 4.55 nF parallel-plate capacitor contains 27.5 μJ of stored energy. By how many volts would you have to increase this potentia
aivan3 [116]

Answer:

\Delta V=V_{2}-V_{1}=45.4V

Explanation:

The energy, E, from a capacitor, with capacitance, C, and voltage V is:

E=\frac{1}{2} CV^{2}

V=\sqrt{2E/C}

If we increase the Voltage, the Energy increase also:

V_{1}=\sqrt{2E_{1}/C}

V_{2}=\sqrt{2E_{2}/C}

The voltage difference:

V_{2}-V_{1}=\sqrt{2E_{2}/C}-\sqrt{2E_{1}/C}

V_{2}-V_{1}=\sqrt{2*55*10^{-6}/4.55*10^{-9}}-\sqrt{2*27.5*10^{-6}/4.55*10{-9}}=45.4V

5 0
3 years ago
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