The answer to your question is C.
I found this on arxsiv.org: “The central force motion between two bodies about their center of mass can be reduced to an equivalent one body problem in terms of their reduced mass m and their relative radial distance r. ... The potential V (r) from which this force is derived is also a function of r alone, F = −VV, V ≡ V (r).”
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Answer:
The smallest diameter is ![D =122 \ m](https://tex.z-dn.net/?f=D%20%3D122%20%5C%20m)
Explanation:
From the question we are told that
The resolution of the telescope is ![\theta = 0.00350 \ arc \ second](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%200.00350%20%5C%20arc%20%5C%20second)
The wavelength is ![\lambda = 1.70 \mu m = 1.70 *10^{-6} \ m](https://tex.z-dn.net/?f=%5Clambda%20%3D%201.70%20%5Cmu%20m%20%3D%201.70%20%2A10%5E%7B-6%7D%20%5C%20m)
From the question we are told that
![1 arc \ sec = \frac{1}{3600^o}](https://tex.z-dn.net/?f=1%20arc%20%5C%20sec%20%3D%20%5Cfrac%7B1%7D%7B3600%5Eo%7D)
So ![0.00350 \ arc \ second = x](https://tex.z-dn.net/?f=0.00350%20%5C%20arc%20%5C%20second%20%3D%20x)
Therefore
![x = 0.00350 * \frac{1}{3600 }](https://tex.z-dn.net/?f=x%20%3D%20%200.00350%20%20%2A%20%20%5Cfrac%7B1%7D%7B3600%20%7D)
![x = ( 9.722*10^{-7} )^o](https://tex.z-dn.net/?f=x%20%3D%20%28%209.722%2A10%5E%7B-7%7D%20%29%5Eo)
Now ![1^o = \frac{\pi}{180}](https://tex.z-dn.net/?f=1%5Eo%20%20%3D%20%20%5Cfrac%7B%5Cpi%7D%7B180%7D)
So ![(9.722*10^{-7})^o = \theta](https://tex.z-dn.net/?f=%289.722%2A10%5E%7B-7%7D%29%5Eo%20%3D%20%20%5Ctheta)
=> ![\theta = (9.722*10^{-7}) * \frac{\pi}{180}](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%20%289.722%2A10%5E%7B-7%7D%29%20%2A%20%5Cfrac%7B%5Cpi%7D%7B180%7D)
![\theta = 1.69*10^{-8} rad](https://tex.z-dn.net/?f=%5Ctheta%20%20%3D%20%201.69%2A10%5E%7B-8%7D%20rad)
The smallest diameter is mathematically represented as
![D = \frac{1.22 \lambda }{\theta }](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B1.22%20%5Clambda%20%7D%7B%5Ctheta%20%20%7D)
substituting values
![D = \frac{1.22 * 1.7 *10^{-6}} {1.69 *10^{-8} }](https://tex.z-dn.net/?f=D%20%3D%20%5Cfrac%7B1.22%20%2A%201.7%20%2A10%5E%7B-6%7D%7D%20%7B1.69%20%2A10%5E%7B-8%7D%20%20%7D)
![D =122 \ m](https://tex.z-dn.net/?f=D%20%3D122%20%5C%20m)
Answer:
The answer is D.
Explanation:
There is no gravity in Space so that means that it will decrease your weight but not your mass.
<h2><u><em>
Please give Brainiest</em></u></h2>
Answer:
correct me if i'm wrong nut i thinks its a The atomic symbol of an element surrounded by valence electrons
Explanation: