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Arisa [49]
3 years ago
8

An 805-kg race car can drive around an unbanked turn at a maximum speed of 54 m/s without slipping. the turn has a radius of cur

vature of 155 m. air flowing over the car's wing exerts a downward-pointing force (called the downforce) of 10600 n on the car. (a) what is the coefficient of static friction between the track and the car's tires? (b) what would be the maximum speed if no downforce acted on the car?
Physics
1 answer:
SIZIF [17.4K]3 years ago
8 0
(a) Equating centripetal force to friction force, one finds the relation
  v² = kar
for car speed v, coefficient of friction k, radius of curvature r, and downward acceleration a.

There is already downward acceleration due to gravity. The additional accceleration due to the wing is
  a = F/m = 10600 N/(805 kg) ≈ 13.1677 m/s²
We presume this is added to the 9.80 m/s² gravity provides, so the coefficient of friction is
  k = v²/(ar) = (54 m/s)²/((13.1677 m/s² +9.80 m/s²)·(155 m))
  k ≈ 0.8191

(b) The maximum speed is proportional to the square root of the downward acceleration. Changing that by a factor of 9.80/(9.80+13.17) changes the maximum speed by the square root of this factor.
  max speed with no wing effect = (54 m/s)√(9.8/22.97) ≈ 35.27 m/s
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Answer:

C) independent variable.

Explanation:

the control was or would be the plant at the window. the dependent is the growth of each plant. the constant is the amount of water

5 0
3 years ago
Help plz I don't understand ​
Vika [28.1K]

#78

Airplane start with initial speed

v_i = 0

now the takeoff velocity is given as

v_f = 300 km/h

v_f = 83.33 m/s

acceelration is given as

a = 1 m/s^2

now we have

v_f - v_i = at

from above equation we have

83.33 - 0 = 1(t)

t = 83.33 s

#79

Airplane start with initial speed

v_i = 0

now the takeoff velocity is given as

v_f = 300 km/h

v_f = 83.33 m/s

acceelration is given as

a = 2 m/s^2

now we have

v_f - v_i = at

from above equation we have

83.33 - 0 = 2(t)

t = 41.7 s

6 0
3 years ago
A student uses an audio oscillator of adjustable frequency to measure the depth of a water well. The student reports hearing two
katrin [286]

Answer:

a)     L = 33.369 m , b) 21

Explanation:

The analysis of the ocean depth can be performed assuming that at the bottom of the ocean there is a node and the surface must have a belly, so the expression for resonance is

         λ = 4 L / n

         n = 1, 3, 5, ...

The speed of the wave is

         v = λ f

        v = 4L / n f

        L = n v / 4f

Let's write the expression for the two frequencies

       L = n₁ 343/4 53.95

       L = n₁ 1,589

       

       L = n₂ 343/4 59

       L = n₂ 1.4539

Let's solve the two equations

       n₁ 1,589 = n₂ 1,459

       n₁ / n₂ = 1.4539 / 1.589

       n₁ / n2 = 0.91498

Since the two frequencies are very close the whole numbers must be of consecutive resonances, let's test what values ​​give this value

  n₁    n₂    n₁ / n₂

  1      3       0.3

  3     5       0.6

  5     7        0.7

  7     9        0.77

  9    11        0.8

  17   19       0.89

  19  21        0.905

  21  23       0.913

  23 25       0.92

Therefore the relation of the nodes is n₁ = 21  and n₂ = 23

Let's calculate

                L = n₁ 1,589

                L = 21  1,589

                L = 33.369 m

b) the number of node and nodes is equal therefore there are 21 antinode

4 0
3 years ago
While trees are not the largest level in the pyramid of numbers, they are still the base for both the pyramids of biomass and py
Oxana [17]
It is true because <span>A pyramid of biomass is a representation of the amount of energy contained in biomass, at different trophic levels for a given point in time . The amount of energy available to one trophic level is limited by the amount stored by the level below. Because energy is lost in the transfer from one level to the next, there is successively less total energy as you move up trophic levels. Tree is a base as it provides food and energy.</span>
6 0
2 years ago
Science help please!
OLga [1]

Answer:

104 N

Explanation:

m = 1300 kg

a = 0.08m/s^2

F = 1300*0.08

F = 104 N

Newtons is the unit of force.

3 0
2 years ago
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