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steposvetlana [31]
3 years ago
6

The field of physics which deals with the study of probability waves that describe the motion and dynamics of particles with mas

s is known as A. nuclear physics. B. quantum mechanics. C. field theory. D. statistical mechanics. E. classical mechanics
Physics
1 answer:
goldenfox [79]3 years ago
4 0

Answer:

Option B. quantum mechanics

Explanation:

Quantum Mechanics, at atomic and sub-atomic levels deal with the study of how particles at this level behave and how the matter and energy interacts.

It also explains the properties of atoms, molecules and the particles constituting these.

The wave- particle duality of quantum mechanics that says that matter or every quantum of it exhibits wave as well as particle nature.

This theory was incorporated with its mathematical description given by Schrodinger was also incorporated in the theory for eave-particle duality and The probability for the existence of particle was determined.

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12 1/2 i would assume
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Calculate the AMA of an access ramp if it takes 255 N of force to push a person in a wheelchair having a combined weight of 764
Andreyy89
Actual Mechanical Advantage(AMA) = Weight / Force
Here, Weight = 764 N
Force = 255 N

Substitute the values in to the expression, 
AMA = 764 / 255
AMA = 2.99

After rounding-off to the nearest tenth value, it would be 3

Finally, option C would be your answer.

Hope this helps!
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Answer:

Explanation:

Force I think

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1. What does the endocrine system have in common with the muscular system?
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A uniform disk of mass M = 4.9 kg has a radius of 0.12 m and is pivoted so that it rotates freely about its axis. A string wrapp
AlekseyPX

Answer:

(A) 2.4 N-m

(B) 0.035kgm^2

(C) 315.426 rad/sec

(D) 1741.13 J

(E) 725.481 rad

Explanation:

We have given mass of the disk m = 4.9 kg

Radius r = 0.12 m, that is distance = 0.12 m

Force F = 20 N

(a) Torque is equal to product of force and distance

So torque \tau =Fr, here F is force and r is distance

So \tau =20\times 0.12=2.4Nm

(B) Moment of inertia is equal to I=\frac{1}{2}mr^2

So I=\frac{1}{2}\times 4.9\times 0.12^2=0.035kgm^2

Torque is equal to \tau =I\alpha

So angular acceleration \alpha =\frac{\tau }{I}=\frac{2.4}{0.035}=68.571rad/sec^2

(C) As the disk starts from rest

So initial angular speed \omega _{0}=0rad/sec

Time t = 4.6 sec

From first equation of motion we know that \omega =\omega _0+\alpha t

So \omega =0+68.571\times  4.6=315.426rad/sec

(D) Kinetic energy is equal to KE=\frac{1}{2}I\omega ^2=\frac{1}{2}\times 0.035\times 315.426^2=1741.13J

(E) From second equation of motion

\Theta =\omega _0t+\frac{1}{2}\alpha t^2=0\times 4.6+\frac{1}{2}\times 68.571\times 4.6^2=725.481rad

3 0
3 years ago
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