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andreev551 [17]
3 years ago
14

A block of 1 kg with a speed 1 m/s hits a spring placed horizontally as shown in the figure. If spring constant is 1000 N/m, fin

d the compression in the spring.
Physics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

0.0316 m

Explanation:

Wok done = Energy change

Work done on the spring = Energy change of the block

  Elastic Potential stored = Kinetic energy of the block

\frac{1}{2} kx^{2} = \frac{1}{2} mv^{2}

                              x = \sqrt{v^{2}\frac{m}{k}  }

                              x = \sqrt{1^{2}\frac{1}{1000}  }

                              x = 0.0316 m

k = spring constant

m = mass of block

v = velocity of the block

x = compression of spring

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A mass of 0.54 kg attached to a vertical spring stretches the spring 36 cm from its original equilibrium position. The accelerat
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Explanation:

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