Question

A block of 1 kg with a speed 1 m/s hits a spring placed horizontally as shown in the figure. If spring constant is 1000 N/m, find the compression in the spring.

Answer 1

Answer:

0.0316 m

Explanation:

Wok done = Energy change

Work done on the spring = Energy change of the block

  Elastic Potential stored = Kinetic energy of the block

$\frac{1}{2} kx^{2} = \frac{1}{2} mv^{2}$

                              x = $\sqrt{v^{2}\frac{m}{k} }$

                              x = $\sqrt{1^{2}\frac{1}{1000} }$

                              x = 0.0316 m

k = spring constant

m = mass of block

v = velocity of the block

x = compression of spring