Question

A conveyer belt moves a 40 kg box at a velocity of 2 m/s. What is the kinetic energy of the box while it is on the conveyor belt?

Answer 1

$Kinetic energy = \frac{mass*velocity ^{2} }{2} = \frac{40*2 ^{2} }{2} = 80J$. Therefore kinetic energy of the box while on the conveyor belt is 80J. 

Answer 2

Answer : The kinetic energy of the box is, 80 J

Explanation :

The formula used for kinetic energy is:

$K.E=\frac{1}{2}mv^2$

where,

K.E = kinetic energy = ?

m = mass = 40 kg

v = velocity = 2 m/s

Now put all the given values in the above formula, we get the kinetic energy of the box while it is on the conveyor belt.

$K.E=\frac{1}{2}mv^2$

$K.E=\frac{1}{2}\times (40kg)\times (2m/s)^2$

$K.E=80kg.m^2/s^2=80J$

Thus, the kinetic energy of the box is, 80 J