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Arisa [49]
3 years ago
6

In an internal combustion engine, the gas vapor/air mixture enters the cylinder during the _____ stroke. intake compression powe

r exhaust
Physics
1 answer:
grigory [225]3 years ago
3 0
The cylinder takes in the gas/air mixture during the intake stroke.
The cylinder compresses the gas/air mixture during the compression stroke.
The gas/air mixture burns and generates power during the power stroke.
The cylinder forces the gas/air mixture out during the exhaust stroke.
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While refrigerant 410a is a near azeotropic refrigerant, it is still best when charging to remove the r-410a as a _______ from t
andreev551 [17]
While refrigerant 410a is a near azeotropic refrigerant, it is still best when charging to remove the r-410a as a liquid from the storage cylinder.
Azeotrope means a constant boiling mixture. it is a mixture of two or more liquids,by simple distillation whose proportions cannot be changed. A mixture behaving purely is azeotropic and the mixture which behave differently is called non-azeotropic.
7 0
4 years ago
In terms of saturation (unsaturated, saturated, super-saturated). How would you classify the following?
miskamm [114]

<u>Answer:</u>

<em>1. A NaCl solution with a concentration of 50g/100mL of water at 40°C:</em> The NaCl solution with a given concentration is saturated at this temperature .As the temperature increases the solution will more dissolves.

<em>2. A sugar solution with a concentration of 200g/100mL of water at 40°C: </em>The sugar solution with a given concentration is saturated at this temperature. As the temperature increases the solution will more dissolves.

<em>3. A sugar solution with a concentration of 240g/100mL of water at 40°C:</em> The sugar solution with a given concentration is saturated at given temperature.

7 0
3 years ago
For a particular pipe in a pipe-organ, it has been determined that the frequencies 296 Hz and 370 Hz are two adjacent natural fr
user100 [1]

Answer:

fundamental frequency of pipe will be equal to 74 Hz

Explanation:

We have given for a particular organ pipe two adjacent frequency are 296 Hz and 370 Hz

Speed of the sound in air is 343 m/sec

We have to find the fundamental frequency for the pipe

Fundamental frequency will be equal to difference of the two adjacent frequency

So fundamental frequency = 370 - 296 = 74 Hz

So fundamental frequency of pipe will be equal to 74 Hz

8 0
3 years ago
Someone please help me Im confuzled.
fenix001 [56]

its a solid from the pressure they put on a tennis ball would make it full of moving at fast speed matter bites compacted together but still moving.

6 0
3 years ago
If the angular velocity of the pully is -8.4rad/s at a given time, and its anglar acceleration is -2.8rad/s2, what is the angula
snow_lady [41]

Here we know that

\omega_i = - 8.4 rad/s

\alpha = - 2.8 rad/s^2

t = 1.5 s

now from kinematics we have

\omega_f = \omega_i + \alpha t

now from above all values we have

\omega_f = (-8.4 rad/s) + (-2.8 rad/s^2)(1.5)

\omega_f = -8.4 + (-4.2)

\omega_f = -12.6 rad/s

so final angular speed is -12.6 rad/s

6 0
3 years ago
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