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galben [10]
3 years ago
8

Suppose a new star cluster is born with one o star, 10 a stars, 100 g stars, and 1000 m stars. which stellar type dominates the

light output from the cluster?
Physics
1 answer:
uranmaximum [27]3 years ago
6 0
Stars<span> are </span>classified<span> by their spectra (the elements that they absorb) and their temperature. There are seven main types of </span>stars. In order of decreasing temperature, O, B, A, F, G, K, and M. Type O stars are the stars with the highest temperature and biggest luminosity. So, if there is a <span>new born star cluster : 1. with one O star,
2. with 10 A stars,
3. with 10 G stars,
4. with 1000 M stars

</span><span>the stellar type O will dominate the light output from the cluster.</span>
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Lina20 [59]

Answer:

0.125m/s^2

Explanation:

20-10=10

10 divided by 80=0.125m/s^2

5 0
3 years ago
A 5,000 kg satellite is orbiting the Earth in a circular path. The height of the satellite above the surface of the Earth is 800
Arada [10]

Explanation:

The given data is as follows.

            m = 5000 kg,            h = 800 km = 0.8 \times 10^{6} m

    R_{e} = 6.37 \times 10^{6} m,    r = R + h = 7.17 \times 10^{6} m

   M_{e} = 5.98 \times 10^{24} kg,   G = 6.67 \times 10^{-11} Nm^{2}/kg^{2}

As we know that,

              \frac{mv^{2}}{r} = \frac{GmM_{e}}{r^{2}}

                      v = \sqrt{\frac{GM_{e}}{r^{2}}}

And, it is known that formula to calculate angular velocity is as follows.

               \omega = \frac{v}{r} = \sqrt{\frac{GM_{e}}{r^{3}}}

                            v = \sqrt{\frac{GM_{e}}{r^{3}}}

                               = \sqrt{\frac{6.67 \times 10^{-11} Nm^{2}/kg^{2} \times 5.98 \times 10^{-24} kg^{-2}}{(7.17 \times 10^{6} m)^{3}}}

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Thus, we can conclude that speed of the satellite is 1.0402 \times 10^{-3} rad/s.

6 0
3 years ago
When making sweet tea, McDonalds adds the sugar while the tea is hot. The sugar is added at this step so that the tea can be as
Lilit [14]

Answer:

d

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we need the tea to be at first moist in order to get much more flavor. then supersaturated so that it increases the concentration of the flavor by it not being too sweet nor too salty. so just right.

3 0
3 years ago
Read 2 more answers
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kakasveta [241]

Answer:

 #_electrons = 2 10¹⁰ electrons

Explanation:

For this exercise we can use a direct rule of three proportions rule. If an electron has a charge of 1.6 10⁻¹⁹ C how many electrons have a charge of 3.2 10⁻⁹ C

          #_electrons = 3.2 10⁻⁹ ( \frac{1}{1.6 \ 10^{-19}})

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7 0
3 years ago
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zmey [24]
The answer should be 741 N.

W=m*g
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8 0
2 years ago
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